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topjm [15]
3 years ago
13

Con base en el tema ley de ohm, resistividad y resistencia resuelva los siguientes

Physics
1 answer:
Bumek [7]3 years ago
3 0
Answer:Explanation:gfgfgfgfgfgfgfgfgfg
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Which correctly lists three places that fresh water is found?
Tju [1.3M]
The answer is underground
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If a 75 W lightbulb is 15% efficient, how many joules of light energy does the bulb produce every minute?
stiks02 [169]

Answer:

1 W = 1 J / sec       Definition of watt is 1 joule / sec

So if a bulb uses 75 J / sec it must use

75 J/s * 60 sec / min = 4500 J/min    energy used by bulb

If bulb is 15% efficient then the light delivered is

P = 4500 J / min * .15 = 675 J / min

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3 years ago
Which state of matter takes both the shape and volume of its container?
Tresset [83]

The <em>gaseous state</em> of matter does that.  A gas expands to take the shape and volume of whatever you put it into.

6 0
3 years ago
Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m
Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}

Substituting,

V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

V_{cm} = 1.034m/s

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where here v_f is the velocity after the collision.

v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}

v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

v_f = 1.034m/s

8 0
3 years ago
What is the voltage in a circuit if the current is 6.2 A and the resistance is 18 ohms? A) 2.9 V B) 11.8 V C) 24.2 V D) 111.6 V
maks197457 [2]

V = I · R  =  (6.2 A) · (18 Ω) =  111.6 volts  (D)
7 0
3 years ago
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