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noname [10]
3 years ago
9

A ball rolled along a horizontal surface maintains a constant speed because

Physics
2 answers:
Oksi-84 [34.3K]3 years ago
7 0
There is no friction witch is impossible but good question.
leva [86]3 years ago
3 0
Gravity is in the vertical direction, so there's no horizontal force on the ball to rob kinetic energy from it. (except friction with the floor and the air ...)
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A car starts from rest and accelerates uniformly over a time of 7.25 seconds for a distance of 210 m. Determine the acceleration
lara31 [8.8K]

Answer:

Acceleration is 7.990487515m/s²

Initial velocity is 0m.s

Explanation:

s=ut+(1/2)at²

210=0(7.25)+(1/2)a(7.25²)

210=26.28125a

∴a=7.990487515m/s²

'Vi' or 'u' is the inital speed. Since it starts from rest, this equals 0.

8 0
2 years ago
) Continuing on Problem 1, assume a strain gage was bonded to the cylinder wall surface in the direction of the axial strain. Th
zzz [600]

Answer:

See attached document

Explanation:

Entire process for deriving the asked expression dV across the bridge as function of dP is illustrated in the attachment below.

The document gives a step-by step process for arriving at the expression. However, manipulation of algebraic equations is skipped for the conciseness of the document.

It also gives the expression for the case when all resistors have different nominal values.

Download docx
6 0
3 years ago
Reflection off of a smooth surface like a mirror is an example of diffuse reflection.
Akimi4 [234]

Answer:

true

Explanation:

Reflection is when light bounces off an object. If the surface is smooth and shiny, like glass, water or polished metal, the light will reflect at the same angle as it hit the surface. ... This is called diffuse reflection. Diffuse reflection is when light hits an object and reflects in lots of different directions.

8 0
3 years ago
Read 2 more answers
A child sits 1.6 m from the center of a merry go round that makes one complete revolution in 4.7 s. What is his angular accelera
olga2289 [7]

Answer: angular acceleration = 2.86\ rad/sec^{2}

Given:

Distance from center of axis = 1.6 m

Time taken to complete one revolution = 4.7 sec

Therefore, we can evaluate the angular acceleration using the following formula:

\alpha = r\times \omega^{2}

\alpha = r\times (\frac{2\pi}{T})^{2}

\alpha = 1.6\times (\frac{2\times3.14}{4.7})^{2}

\alpha = 2.86\ rad/sec^{2}

7 0
3 years ago
Which of the following graphs represents constant positive acceleration
nika2105 [10]
W, because as time is moving up at a consistent rate the speed is as well, creating the straight line.
5 0
3 years ago
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