A ball rolled along a horizontal surface maintains a constant speed because
2 answers:
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Well we can just use F=ma. The force is 10N, the mass is 50 kg, solve for a. Well since we kg and N, no conversion is necessary. So just plugging in the numbers, we get
10N = 50 kg · a
A newton is just
The s^2 and 50 kg you multiply
The kg's cancel and 10/50 is 1/5
So the acceleration is 1/5 m/s^2
Answer:
The ball fell 275.625 meters after 7.5 seconds
Explanation:
<u>Free fall </u>
If an object is left on free air (no friction), it describes an accelerated motion in the vertical direction, powered exclusively by the acceleration of gravity. The formulas needed to compute the different magnitudes involved are
Where is the final speed of the object in free fall, assumed positive downwards, t is the time elapsed since the release and y is the vertical distance traveled by the object
The ball was dropped from a cliff. We need to calculate the vertical distance the ball went down in t=7.5 seconds. We'll use the formula