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Aleksandr [31]
3 years ago
13

A boy on the beach holds a spherical balloon filled with air. at 10:00am, the temperature on the beach is 20°c and the balloon h

as a diameter of 30 cm. two hours later, the balloon diameter is 30.5 cm. assume that the air is an ideal gas and that no air was lost or added, what is the temperature on the beach at noon?
Physics
1 answer:
Anon25 [30]3 years ago
6 0
For idea gases, volume is directly proportional to temperature. That is, an increase in temperature leads to increase in volume and vice versa.

Therefore,
V1/T1 = V2/T2 => T2 = (V2*T1)/V1

Assuming that the balloon is spherical in shape,

V= 4/3*pi*R^3.... In the formula for calculating T2, 4/3*pi cancels out.

R1 = 30/2 15 cm; R2 = 30.5/2 = 15.25 cm; T1 = 20+273.15 =293.15 K

Therefore,

T2 = (R2^3*T1)/R1^3 = (15.25^3*293.15)/15^3 = 308.05 K = 34.9 °C
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Answer:

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A steel spur pinion has a module of 2 mm, 17 teeth cut on the 20° full-depth system, and a face width of 20 mm. At a speed of 16
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Answer:

The value of bending stress on the pinion 35.38 M pa

Explanation:

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m = 2 mm

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\sigma = \frac{K_{v} F}{m b y}

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