The size of a balloon increases when the pressure inside it increases. The balloon gets bigger when it is left in the heat from
1 answer:
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Answer:
a-1 Graph is attached. The relation is linear.
a-2 The corresponding height for 68 kPa Pressure is 7.54 m
a-3 The corresponding weight for 68 kPa Pressure is 1394726kg
b The original height of the column is 5.98 m
Explanation:
Part a
a-1
The graph is attached with the solution. The relation is linear as indicated by the line.
a-2
By the equation
Here
- P is the pressure which is given as 68 kPa.
- ρ is the density of the oil whose SG is 0.92. It is calculated as
- g is the gravitational constant whose value is 9.8 m/s^2
- h is the height which is to be calculated
So the height of column is 7.54m
a-3
By the relation of volume and density
Here
- ρ is the density of the oil which is 920 kg/m^3
- V is the volume of cylinder with diameter 16m calculated as follows
Mass is given as
So the mass of oil leading to 68kPa is 1394726kg
Part b
Pressure variation is given as
Now corrected pressure is as
Finding the value of height for this corrected pressure as
The original height of column is 5.98m
Answer:
b) TA = TB = TC
Explanation:
- When put in contact each other, and isolated, both blocks will exchange heat till they reach to thermal equilibrium.
- During this process, the body at a higher temperature, will loss heat, tat it will be gained by the other body.
- The equilibrium condition will be reached when the following equation be met:
- Replacing by the values of T₀A = 300º C, and T₀B = 400ºC, and simplifying common terms as mA = mB, we can solve for Tfin, as follows:
- So, when both blocks reach to equilibrium, they will be at a common final temperature, 350ºC.
- When put in contact with block C, at the same temperature, at that instant, the three blocks will have the same common temperature of 350 ºC.
- So, option b) is the right one.