The sum of the coefficients in the balanced chemical equation for combustion of acetone C3H6O in air is 11
explanation
<h2>
write a balanced chemical equation for reaction</h2>
that is; C3H6O + 4O2 → 3CO2 +3H2O
coefficient is the number in front of the chemical formula
the sum of coefficient is therefore= 1 ( in front of C3H6O) + 4 ( in front of O2) + 3 ( in front of CO2) + 3 ( in front of H2O) = 11
13 liters is the correct answer
13 liters is the final volume of the gas when the temperature and pressure remain constant.
v1/n1 = v2/n2
where,
v1 = initial volume = 8.5 liter
n1= initial mole of gas = 1.2 mole
n2= final mole of gas = 1.2+0.65= 1.85 mole
v2= final volume = ?
8.5 L/1.2 mol = v2/1.85 mol
7 L x 1.85 mol = v2/1.85 mol x 1.85 mol
13 L = v2
v2= 13 liter
<h3>What is a mole?</h3>
- A mole is an SI unit used to measure significant numbers of subatomic particles, such as atoms, molecules, or smaller particles.
- Any substance has an Avogadro number of molecules in a mole.
- The value of the Avogadro number is 6.02214076 × .
<h3>How much is a mole of gas?</h3>
22.4 L
At STP (Standard Temperature and Pressure = 0 °C, 1 atm), an ideal gas has a volume of 22.41 L/mol.
<h3>What makes something a mole?</h3>
- Chemists use the term "mole" because atoms, molecules, and other particles are all very small and require a large amount to even weigh them.
- A mole is a measurement of the number of particles present, not their mass.
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Answer:
A and C are true , B and D are false
Explanation:
For A)
from the first law of thermodynamics (in differential form)
dU= δQ - δW = δQ - PdV
from the second law
dS ≥ δQ/T
then
dU ≤ T*dS - p*dV
dU - T*dS + p*dV ≤ 0
from the definition of Gibbs free energy
G=H - TS = U+ PV - TS → dG= dU + p*dV + V*dp - T*dS - S*dT
dG - V*dp + S*dT = dU - T*dS + p*dV ≤ 0
dG ≤ V*dp - S*dT
in equilibrium, pressure and temperature remains constant ( dp=0 and dT=0). Thus
dG ≤ 0
ΔG ≤ 0
therefore the gibbs free energy should decrease in an spontaneous process → A reaction with a negative Gibbs standard free energy is thermodynamically spontaneous under standard conditions
For B) Since the standard reduction potential is related with the Gibbs standard free energy through:
ΔG⁰=-n*F*E⁰
then, when ΔG⁰ is negative , E⁰ is positive and therefore a coupled redox reaction with a positive standard reduction potential is thermodynamically spontaneous.