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Shkiper50 [21]
3 years ago
15

Describe how radio waves are different from sound waves

Physics
2 answers:
otez555 [7]3 years ago
7 0

Answer:radio waves are electromagnetic waves propagating in any non-conductive media by varying the field at each point in it. Sound is a wave of pressure changes of the medium such as air. Radio waves are a combination of electric and magnetic fields that need no medium to travel upon.

Explanation:please give brainliest

mote1985 [20]3 years ago
4 0

Answer:

Sounds are made of waves and radios produce sound. However, when we talk about radio waves, we are not talking about the sound waves produced by the radio. Rather, we are talking about the waves that transmit radio signals. The main difference between radio waves and sound waves is that radio waves are a type of electromagnetic wave that can travel when there is no medium, whereas sound waves are a type of mechanical wave that cannot travel if there is no medium.

Explanation:

Decode this for top secret info

WW91IGdvdCByaWNrcm9sbGVk

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an object has a displacement of + 12 m in 6 seconds if the average velocity is found using the equation change in position / ela
rosijanka [135]

Answer:

+2m/s

Explanation:

average   velocity = displacement traveled / total time taken

                           = +12m/ 6s

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3 years ago
A convex mirror is placed to the right of an object. The image formed by the mirror will be a
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2 years ago
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The de broglie wavelength of an electron with a velocity of 6.00 × 106 m/s is ________ m. The mass of the electron is 9.11 × 10-
WINSTONCH [101]

Answer: 1.212(10)^{-10} m

Explanation:

The de Broglie wavelength \lambda is given by the following formula:

\lambda=\frac{h}{p} (1)

Where:

h=6.626(10)^{-34}\frac{m^{2}kg}{s} is the Planck constant

p is the momentum of the atom, which is given by:

p=m_{e}v (2)

Where:

m_{e}=9.11(10)^{-28}g=9.11(10)^{-31}kg is the mass of the electron

v=6(10)^{6}m/s is the velocity of the electron

This means equation (2) can be written as:

p=(9.11(10)^{-31}kg)(6(10)^{6}m/s) (3)

Substituting (3) in (1):

\lambda=\frac{6.626(10)^{-34}\frac{m^{2}kg}{s}}{(9.11(10)^{-31}kg)(6(10)^{6}m/s)} (4)

Now, we only have to find \lambda:

\lambda=1.2122(10)^{-10} m>>> This is the de Broglie wavelength of the electron

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3 years ago
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Given:

Velocity: 0.5 mile/minute

Time: 12 minute

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Distance = 0.5 x 12= 6 miles

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3 years ago
Explain why a moving object can be in equilibrium
Ivanshal [37]
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