Calculate the mole fraction of each solute and solvent in the solution of 46.85 g of codeine, C 18 H 21 NO 3 , in 125.5 g of eth
anol, C 2 H 5 OH.
1 answer:
mol fraction Codein : 0.054
mol fraction Ethanol : 0.946
<h3>Further explanation</h3>
Given
46.85 g of codeine
125.5 g of ethanol
Required
mol fraction
Solution
The mole fraction : the mole ratio of a substance to the mole of solution /mixture
mol Codeine, C₁₈H₂₁NO₃(MW=299.4 g/mol) :

mol Ethanol, C₂H₅OH(MW=46.07 g/mol)

mol of solution :


mol fraction Ethanol :

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