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2 years ago

Which statement is true of discrete data?

Mathematics

1 answer:

Lana71 [14]2 years ago

5 0

Answer:

The first 2 statements are true.

Step-by-step explanation:

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Evaluate each of the following to three significant figures, and express each answer in SI units using an appropriate prefix: (a

Softa [21]

Answer:

a). $4.86\times 10^{-15}$ m

b). $4.21\times 10^{-2}$ m³

c). $7.00\times 10^{3}$ N²

Step-by-step explanation:

In this question we have to convert each option into SI units.

a). $4.86(10^{-6})^{2}$ mm

= $4.86\times (10^{-12})\times (10^{-3} )$ m

= $4.86\times 10^{-15}$ m

b). (348 mm)³

= $(348)^{3}\times (10^{-3})^{3}$ m³

= $42144192\times 10^{-9}$ m³

= $4.21\times 10^{-2}$ m³

c). $(83700)^{2}\times (10^{-3})^{2}$ N²

= $700569\times 10^{4}\times 10^{-6}$ N²

= $7.00\times 10^{9}\times 10^{-6}N^{2}$

= $7.00\times 10^{3}$ N²

7 0

2 years ago

Amy's math notebook weighs 1/2 pound, her science notebook weighs 7/8 pound, and her history notebook weighs 3/4 pound. What are

QveST [7]

1/2 is equal to 50%, 3/4 is equal to 75%, and 7/8 is equal to 87.5 percent. Therefore, the order is 1/2, 3/4, and then 7/8.

4 0

2 years ago

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The date of death for a widow was 2019. If the estate was valued at $2,186,000 and the estate was taxed at 40 percent, what was

Airida [17]

Answer:

Value of tax liability will be zero

Step-by-step explanation:

Given:

Total estate value = $2,186,000

Estate tax = 40 %

Find:

Heir's tax liability = ?

Computation:

Total taxable estate = Total estate value - Estate Exemption

Note: According to Exhibit 19-6 for Estate Exemption, Estate Exemption is 11.4 million.

We know that Estate Exemption is higher than total estate value, therefore will be no tax liability on the successor, so the value of tax liability will be zero.

7 0

2 years ago

Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

1 year ago

the total wages Jimmy makes at a local ice cream shop vary directly with the number of hours he works . He makes $8.50 per hour.

bearhunter [10]

Answer:

Step-by-step explanation:

8 0

2 years ago

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