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solniwko [45]
3 years ago
12

What organism is grass

Chemistry
1 answer:
Aleks04 [339]3 years ago
7 0

Answer:

green

Explanation:

You might be interested in
Zn(s) + HCl(aq) → ZnCl2(aq) + H2(g) ↑
WINSTONCH [101]

Hey there!

Zn + HCl → ZnCl₂ + H₂

First, balance Cl.

1 on the left, 2 on the right. Add a coefficient of 2 in front of HCl.

Zn + 2HCl → ZnCl₂ + H₂

Next, balance H.

2 on the left, 2 on the right. Already balanced.

Lastly, balance Zn.

1 on the left, 1 on the right. Already balanced.

Our final balanced equation:

Zn + 2HCl → ZnCl₂ + H₂

Hope this helps!

6 0
3 years ago
If a system has 2.00 × 10 2 kcal 2.00×102 kcal of work done to it, and releases 5.00 × 10 2 kJ 5.00×102 kJ of heat into its surr
max2010maxim [7]

Answer:

336.8 kilo Joules is the change in internal energy of the system.

Explanation:

The equation for first law of thermodynamics follows:

\Delta U=Q+W

where,

Q = heat added to the system

ΔU = Change in internal energy

W = work done

We have :

Amount of heat given out by the system will be negatuive as heat relased by the system = Q

Q= -5.00\times 10^2 kJ

Work done on the system will positive as work is done on the system:

w = 2.00\times 10^2 kCal=836.8 kJ

\Delta U=-5.00\times 10^2 kJ+836.8 kJ=336.8 kJ

336.8 kilo Joules is the change in internal energy of the system.

4 0
3 years ago
Analyze the data and determine the actual concentration of calcium chloride in the solution. Show all calculations and report in
Rus_ich [418]

Answer:

2.21% wt/v

Explanation:

The mass/volume percentage, %wt/v, is an unit of concentration used in chemistry defined as 100 times the ratio of the mass of solute in g (In this case, CaCl2 = 1.77g) and the volume of solution in mL = 80mL

The %wt/v of this solution is:

%wt /v = 1.77g / 80mL * 100

%wt/v = 2.21% wt/v

6 0
3 years ago
One mole of an ideal gas, for which CV,m = 3/2R, initially at 298 K and 1.00 × 105 Pa undergoes a reversible adiabatic compressi
oksian1 [2.3K]

Answer:

  • final temperature (T2) = 748.66 K
  • ΔU = w = 5620.26 J
  • ΔH = 9367.047 J
  • q = 0

Explanation:

ideal gas:

  • PV = RTn

reversible adiabatic compression:

  • δU = δq + δw = CvδT

∴ q = 0

∴ w = - PδV

⇒ δU = δw

⇒ CvδT = - PδV

ideal gas:

⇒ PδV + VδP = RδT

⇒ PδV = RδT - VδP = - CvδT

⇒ RδT - RTn/PδP = - CvδT

⇒ (R + Cv,m)∫δT/T = R∫δP/P

⇒ [(R + Cv,m)/R] Ln (T2/T1) = Ln (P2/P1) = Ln (1 E6/1 E5) = 2.303

∴ (R + Cv,m)/R = (R + (3/2)R)/R = 5/2R/R = 2.5

⇒ Ln(T2/T1) = 2.303 / 2.5 = 0.9212

⇒ T2/T1 = 2.512

∴ T1 = 298 K

⇒ T2 = (298 K)×(2.512)

⇒ T2 = 748.66 K

⇒ ΔU = Cv,mΔT

⇒ ΔU = (3/2)R(748.66 - 298)

∴ R = 8.314 J/K.mol

⇒ ΔU = 5620.26 J

⇒ w = 5620.26 J

  • H = U + nRT

⇒ ΔH = ΔU + nRΔT

⇒ ΔH = 5620.26 J + (1 mol)(8.314 J/K.mol)(450.66 K)

⇒ ΔH = 5620.26 J + 3746.787 J

⇒ ΔH = 9367.047 J

8 0
3 years ago
Hi do you know this?​
AURORKA [14]

Answer:

2

Explanation

It seems logical

6 0
3 years ago
Read 2 more answers
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