Can alluminium sulphate or carbonate test the purity of water
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To know how many grams of Ammonium Chloride ( a solid) you'll need to make 1.50 L of a 0,01 M solution you'll need to use the definition of molar concentration (M=mol/L) in the following way:
So, you'll need to dissolve 0,8023 g of Ammonium Chloride in 1,5 L of water to make this solution.
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To know how many grams of Ammonium Chloride ( a solid) you'll need to make 1.50 L of a 0,01 M solution you'll need to use the definition of molar concentration (M=mol/L) in the following way:
So, you'll need to dissolve 0,8023 g of Ammonium Chloride in 1,5 L of water to make this solution.
Have a nice day!
The reaction between zinc and silver nitrate is
Moles of Zn = m /M = 599 /65 = 9.2 mol
Moles of AgNO3 = m /M = 1500 /169 = 8.87 mol
Silver nitrate is reacting completely to give silver
Thus, moles of Silver nitrate is equivalent to silver = 8.87
For mass of silver produced
m /M = 8.87 = m /107
m = 949.24 g
Hence, the given quantity of reactants are sufficient to produce 800 g of silver as the amount of silver produced is 949.24 g