<h2>
Answer: 8.93 g/cm³</h2>
<h3>
Explanation:</h3>
Density = mass ÷ volume
= 217.0 g ÷ 24.3 cm³
= 8.93 g/cm³
<h3>∴ the unknown sample of mass 217.0 grams and volume of 24.3 cm³ has a density of 8.93 g/cm³.
</h3>
Heyo,
Sugar is a pure substance. A pure substance is a substance that has chemical properties. Sugar is a pure substance.
Answer:
In a compound, chemical energy is _____required__________ when bonds break.
To solve this, we can use two equations.
t1/2 = ln 2 / λ = 0.693 / λ
where, t1/2 is half-life and λ is the decay constant.
t1/2 = 10 min = 0.693 / λ
Hence, λ = 0.693 / 10 min - (1)
Nt = Nο e∧(-λt)
Nt = amount of atoms at t =t time
Nο= initial amount of atoms
t = time taken
by rearranging the equation,
Nt/Nο = e∧(-λt) - (2)
From (1) and (2),
Nt/Nο = e∧(-(0.693 / 10 min) x 20 min)
Nt/Nο = 0.2500
Percentage of remaining nuclei = (nuclei at t time / initial nuclei) x 100%
= (Nt/Nο ) x 100%
= 0.2500 x 100%
= 25.00%
Hence, Percentage of remaining nuclei is 25.00%
Basic radicals (cations) have been divided into groups based on Ksp values
