All categories

3 years ago

Help please!!!

Physics

1 answer:

exis [7]3 years ago

3 0

Answer:

5 years worth of work (aka all of the homework i currently have)

You might be interested in

A Van de Graaff generator is charged with 2.82 x 106C of positive charge.

Anvisha [2.4K]

B becuse that’s is right

3 0

3 years ago

The free-fall acceleration at the surface of planet 1 is 22 m/s^2. The radius and the mass of planet 2 are twice those of planet

algol13

Answer:

g₂ = 11 m/s²

Explanation:

The value of free-fall acceleration on the surface of a planet is given by the following formula:

$g = \frac{Gm}{r^2}$

where,

g = free-fall acceleration

G = Universal Gravitational Constant

m = mass of the planet

r = radius of planet

FOR PLANET 1:

$g_1 = \frac{Gm_1}{r_1^2}\\\\\frac{Gm_1}{r_1^2} = 22 m/s^2$ --------------------- equation (1)

FOR PLANET 2:

$g_2 = \frac{Gm_2}{r_2^2}\\\\g_2 = \frac{G(2m_1)}{(2r_1)^2}\\\\g_2 = \frac{1}{2}\frac{Gm_1}{r_1^2}\\\\$

using equation (1):

$g_2 = \frac{g_1}{2}\\\\g_2 = \frac{22\ m/s^2}{2}$

8 0

2 years ago

telo118 [61]

Ik what it is hit me up for it

5 0

3 years ago

A child sleds down a hill with an acceleration of 2.94 m/s2. If her initial speed is 0.0 m/s and her final speed is 17.5 m/s, ho

hram777 [196]

Answer:

The child will take 5.952 seconds to travel from the top of the hill to the bottom.

Explanation:

Given that the child accelerates uniformly and that both initial ( $v_{o}$ ) and final speeds ( $v_{f}$ ), measured in meters per second, and acceleration ( $a$ ), measured in meters per square second, are known, we proceed to use the following kinematic equation to determine the time taken to travel from the top of the hill to the bottom ( $t$ ), measured in seconds, is:

$t = \frac{v_{f}-v_{o}}{a}$ (1)

If we know that $v_{o} = 0\,\frac{m}{s}$ , $v_{f} = 17.5\,\frac{m}{s}$ and $a = 2.94\,\frac{m}{s^{2}}$ , then the time taken is:

$t = \frac{17.5\,\frac{m}{s}-0\,\frac{m}{s} }{2.94\,\frac{m}{s^{2}} }$

$t = 5.952\,s$

The child will take 5.952 seconds to travel from the top of the hill to the bottom.

8 0

3 years ago

Why are there temperature differences on the moon's surface even though there is no atmosphere present?

nika2105 [10]

The lack of an atmosphere means convection cannot happen on the moon. Therefore, there is no form of heat dissipation on regions in direct sunlight. In addition, the lack of an atmosphere means there is no greenhouse effect on the moon. This is why regions facing away from sunlight are very cold.

4 0

3 years ago