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Lilit [14]
3 years ago
11

Help please!!!

Physics
1 answer:
exis [7]3 years ago
3 0

Answer:

5 years worth of work (aka all of the homework i currently have)

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It is the disturbance or oscillation that travels through space and matter, accompanied by a transfer of energy.
Gnesinka [82]

Answer:

wave

Explanation:

A wave is defined as the disturbance that causes the movement of energy. The energy is transferred as the waves move from one place to another. A medium is required for the transfer of energy. Usually a wave travels through air or water. The process is carried on at a specific speed that is termed as the speed of propagation.

3 0
2 years ago
two charges + 2.6 uc and -5.4uc experience an attractive force of 6.5mN. What is the separation between the charges?
djyliett [7]

Answer:

...

Explanation:

....

7 0
3 years ago
Sound, light, feelings and ideas are not
taurus [48]
I think it’s A, I’m so sorry if I’m wrong.
6 0
3 years ago
A busy chipmunk runs back and forth along a straight line of acorns that has been set out between his burrow and a nearby tree.
saveliy_v [14]

Answer: a = 1.32m/s2

Therefore, the average acceleration is 1.32m/s2

Explanation:

Acceleration is the rate of change in the velocity per time

a = change in velocity/time

a = ∆v/t

average acceleration a = (v2 -v1)/t. ....1

Given;

Final velocity v2 = 1.63m/s

Initial velocity v1 = -1.15ms

time taken t = 2.11s

Substituting into eqn 1

a = [1.63 - (-1.15)]/2.11

a = (1.63+1.15)/2.11

a = 2.78/2.11

a = 1.32m/s2

Therefore, the average acceleration is 1.32m/s2

6 0
3 years ago
If an object force of 50 N is used to move an object a distance of 20 m, what distance must the object be moved if the input for
steposvetlana [31]

Answer:

\ d_{out} = 100 \ m.

Explanation:

Given data:

F_{in} = 50 \ \rm N

F_{out} = 10 \ \rm N

d_{in} = 20 \ m

Let the distance traveled by the object in the second case be d_{out}.

In the given problem, work done by the forces are same in both the cases.

Thus,

W_{in} = W_{out}

F_{in}.d_{in} = F_{out}.d_{out}

\Rightarrow \ d_{out} = \frac{F_{in}.d_{in}}{F_{out}}

\ d_{out} = \frac{50 \times 20}{10}

\ d_{out} = 100 \ m.

5 0
3 years ago
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