All categories

3 years ago

The second type of wave produced by an earthquake is an S wave (secondary wave), which is a transverse wave. It produces:

Physics

2 answers:

AysviL [449]3 years ago

8 0

Answer:

B) an up-and-down motion on the surface of the earth

Explanation:

The S waves are seismic waves that are produced when an earthquake happens, and they can only travel through solid mediums, this means that they create the up and down motion on the surface of the earth, the waves that create the back and forth motion on the surface are the P waves. The image can help you better understand it.

Mrac [35]3 years ago

4 0

The motion would be best described as B) an up-and-down motion on the surface of the earth

You might be interested in

A vertical spring with stiffness k originally is at rest with no mass attached. Then, a mass M is attached, and the spring rocks

Alina [70]

Answer:

The position of the spring in terms of g, m & k is $x = \frac{m g}{k}$

Explanation:

Stiffness of the spring = k

Mass = m

When a mass m is attached with the spring then spring stretched. in that case the force exerted on the spring is equal to weight of the mass attached.

⇒ Force exerted on the spring F = k x

⇒ m g = k x

⇒ $x = \frac{m g}{k}$

This is the position of the spring in terms of g, m & k.

8 0

3 years ago

A miniature quadcopter is located at x = -2.25 m and y, - 5.70 matt - 0 and moves with an average velocity having components Vv,

kupik [55]

Recall that average velocity is equal to change in position over a given time interval,

$\vec v_{\rm ave} = \dfrac{\Delta \vec r}{\Delta t}$

so that the x-component of $\vec v_{\rm ave}$ is

$\dfrac{x_2 - (-2.25\,\mathrm m)}{1.60\,\mathrm s} = 2.70\dfrac{\rm m}{\rm s}$

and its y-component is

$\dfrac{y_2 - 5.70\,\mathrm m}{1.60\,\mathrm s} = -2.50\dfrac{\rm m}{\rm s}$

Solve for $x_2$ and $y_2$ , which are the x- and y-components of the copter's position vector after t = 1.60 s.

$x_2 = -2.25\,\mathrm m + \left(2.70\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{x_2 = 2.07\,\mathrm m}$

$y_2 = 5.70\,\mathrm m + \left(-2.50\dfrac{\rm m}{\rm s}\right)(1.60\,\mathrm s) \implies \boxed{y_2 = 1.70\,\mathrm m}$

Note that I'm reading the given details as

$x_1 = -2.25\,\mathrm m \\\\ y_1 = -5.70\,\mathrm m \\\\ v_x = 2.70\dfrac{\rm m}{\rm s}\\\\ v_y=-2.50\dfrac{\rm m}{\rm s}$

so if any of these are incorrect, you should make the appropriate adjustments to the work above.

8 0

3 years ago

Whats the difference between an inner planet and an outer planet

Kryger [21]

The outer planets are further away, larger and made up mostly of gas. The inner planets (in order of distance from the sun, closest to furthest) are Mercury, Venus, Earth and Mars. After an asteroid belt comes the outer planets, Jupiter, Saturn, Uranus and Neptune.

8 0

2 years ago

Read 2 more answers

If the mass of an object stays the same and you apply more force what will happen to the objects motion

vovikov84 [41]

it will move the object if you apply force, because of that it will stay the same with newton's law.

4 0

2 years ago

What are the characteristics of high energy wave lengths

Darya [45]

The characteristics of high energy wave length are:
- High Frequencies
- Short wave length
And in term of color, it will be located on the red spectrum.

3 0

3 years ago