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Yanka [14]
3 years ago
13

a tiger leaps horizontally from a 5.7m high rock with a speed of 4.1m/s. How far from the base of the rock will she land

Physics
1 answer:
shepuryov [24]3 years ago
6 0
Looks like a projectiles problem, with the tiger as the projectile. See enclosed for guidance.For more information/help, please ask.ps there's a poem which contains the lines "Tyger tyger burning bright, in the forest of the night; what immortal hand or eye; could frame thy fearful symmetry ?"

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Water flows over a section of Niagara Falls at the rate of 1.2×106 kg/s and falls 50.0 m. How much power is generated by the fal
quester [9]

Answer:

5.88×10⁸ W

Explanation:

Power = energy / time

P = mgh / t

P = (m/t) gh

P = (1.2×10⁶ kg/s) (9.8 m/s²) (50.0 m)

P = 5.88×10⁸ W

7 0
2 years ago
Which of the following is an arithmetic sequence? A. 2, 1, 4, 3, 6, 5, …
sergey [27]

Explanation:

it is not a arithmetic sequence

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2 years ago
What purpose does a female pine cone serve?
Dimas [21]
The answer is <span>It protects the seed until it matures.

Through the process of elimination:
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5 0
2 years ago
Read 2 more answers
A block lies on a horizontal frictionless surface. A horizontal force of 100 N is applied to the block giving rise to an acceler
KIM [24]

Answer:

(a) m = 33.3 kg

(b) d = 150 m

(c) vf = 30 m/s

Explanation:

Newton's second law to the block:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration  (m/s²)

Data

F= 100 N

a= 3.0 m/s²

(a) Calculating of the  mass of the block:

We replace dta in the formula (1)

F = m*a

100 =  m*3

m = 100 / 3

m = 33.3 kg

Kinematic analysis

Because the block  moves with uniformly accelerated movement we apply the following formulas:

d= v₀t+ (1/2)*a*t² Formula (2)

vf= v₀+a*t   Formula (3)

Where:  

d:displacement in meters (m)  

t : time interval in seconds (s)

v₀: initial speed in m/s  

vf: final speed in m/s  

a: acceleration in m/s²

Data

a= 3.0 m/s²

v₀= 0

t = 10 s

(b) Distance the block will travel if the force is applied for 10 s

We replace dta in the formula (2):

d= v₀t+ (1/2)*a*t²

d = 0+ (1/2)*(3)*(10)²

d =150 m

(c) Calculate the speed of the block after the force has been applied for 10 s

We replace dta in the formula (3):

vf= v₀+a*t

vf= 0+(3*(10)

vf= 30 m/s

4 0
3 years ago
g Two mirrors are touching so they have an angle of 35.4 degrees with one another. A light ray is incident on the first at an an
Mamont248 [21]

Answer:

add the angles

HOPE you understand

5 0
2 years ago
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