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Daniel [21]
3 years ago
6

P.1.3b Four candy stores are competing with each other. Which store offers the best buy for candy? A.) Sweet Store: 12 pack for

$3.00 B.) Delicious Treats: 22 pack for $4.62 C.) Sugar Factory: 18 pack for $5.40 D.) Chocolate Shop: 36 pack for $7.20
Mathematics
1 answer:
marin [14]3 years ago
3 0

Answer:

c

Step-by-step explanation:

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Answer:

A X + 3y = 18

Step-by-step explanation:

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Round it to 1lolollololo
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Solve 15 x 14 <br> A. 200<br> B.120<br> C.225<br> D.210
GREYUIT [131]
The answer is D

Hope this helps!
5 0
3 years ago
Read 2 more answers
PLLLLEEEEEEAAASSSSSSSSEEEE
mrs_skeptik [129]

Given:

Line a passes through (2, 10) and (4, 13).

Line b passes through (4, 9) and (6, 12).

Line c passes through (2, 10) and (4, 9).

To find:

Which of the lines, if any are perpendicular.

Solution:

If a line passes through two points, then the slope of line is

m=\dfrac{y_2-y_1}{x_2-x_1}

Line a passes through (2, 10) and (4, 13).  So, slope of this line is

m_a=\dfrac{13-10}{4-2}=\dfrac{3}{2}

Line b passes through (4, 9) and (6, 12).  So, slope of this line is

m_b=\dfrac{12-9}{6-4}=\dfrac{3}{2}

Line c passes through (2, 10) and (4,9).  So, slope of this line is

m_c=\dfrac{9-10}{4-2}=\dfrac{-1}{2}

Product of slopes of to perpendicular lines is -1.

m_a\cdot m_b=\dfrac{3}{2}\times \dfrac{3}{2}=\dfrac{9}{4}\neq -1

m_b\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1

m_a\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1

Therefore, any of these lines are not perpendicular to each other.

8 0
3 years ago
The product of these slopes is ______.This product shows that the slopes are negative reciprocals. It is given that the lines ar
Arturiano [62]

Answer:

- 1

Step-by-step explanation:

Let the slope of one line be 's' , then according to the given condition that the  slope of second line is negative reciprocal of the first , We obtain the slope of the second line as \frac{-1}{s}.

So, the product of both the slopes is given by s\cdot \frac{-1}{s}=-1

This shows that whatever the slopes may be if they are negative reciprocal of each other then their product will always be -1


6 0
3 years ago
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