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Vinvika [58]
2 years ago
11

I NEED THE ANSWER ASAP

Physics
1 answer:
Tems11 [23]2 years ago
6 0

Answer:

what the heck you're really given that much of points

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2. A ball is released from a vertical height of 20 cm. It rolls down a "perfectly
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20 cm

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Given that a ball is released from a vertical height of 20 cm. It rolls down a "perfectly frictionless" ramp and up a similar ramp. What vertical height on the second ramp will the ball reach before it starts to roll back down?

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Two cars, both of mass m, collide and stick together. Prior to the collision, one car had been traveling north at a speed 2v, wh
mel-nik [20]

Answer:u=\frac{v}{2}\sqrt{5-4sin\phi }

Explanation:

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and solving problem in Vertical and horizontal direction

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Conserving Momentum in Vertical direction

m(2v)+m(-vsin\phi )=2m(ucos\theta )

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Conserving momentum in x direction

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4u^2=5v^2-4v^2sin\phi

u=\frac{v}{2}\sqrt{5-4sin\phi }

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