Answer:
<h2>
work done= 48.96 kJ</h2>
Explanation:
Given data
mass of load m= 425 kg
height/distance h=64 m
acceleration a= 1.8 m/s^2
The work done can be calculated using the expression
work done= force* distance
but force= mass *acceleration
hence work done= 425*1.8*64= 48,960 J
work done= 48.96 kJ
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If the observer is moving away from the source ((Figure)), the observed frequency can be found: λs=vTo−voTovTs=(v−vo)Tov(1fs)=(v−vo)(1fo)fo=fs(v−vov).
Power = (voltage) x (current)
13 watts = (6 volts) x (current)
Divide each side by (6 volts):
Current = (13 watts) / (6 volts)
Current = (13/6) Amperes
<em>Current = 2.17 Amperes</em>
The best illustration that represents the interaction is D
Energy is released or absorbed ,but no loss in total molecules,each of which consists of one atom of oxygen and two of hydrogen,are broken down.!
