Answer:
337k
Explanation:
First, let us find the difference between the given two temperatures.
Difference = 85°C - 21°C
= 64°C
<u>And now we have to write the temperature in kelvins.</u>
To convert Celcius to Kelvins you can add 273 to the temperature in Celcius.
<u>Let us find it now.</u>
64°C + 273 = 337k
Therefore,
64°C ⇒ <u>337k</u>
Explanation:
It is given that,
Force applied to object, ![F=(2i+3j)\ N](https://tex.z-dn.net/?f=F%3D%282i%2B3j%29%5C%20N)
Position,
(b) The cross product of force and position vector is used to find the net torque about the z axis. It is given by :
![\tau=F\times r](https://tex.z-dn.net/?f=%5Ctau%3DF%5Ctimes%20r)
![\tau=(2i+3j) \times (4i+5j)](https://tex.z-dn.net/?f=%5Ctau%3D%282i%2B3j%29%20%5Ctimes%20%284i%2B5j%29)
![\tau=\begin{pmatrix}0&0&-2\end{pmatrix}](https://tex.z-dn.net/?f=%5Ctau%3D%5Cbegin%7Bpmatrix%7D0%260%26-2%5Cend%7Bpmatrix%7D)
or
![\tau=(-2k)\ N-m](https://tex.z-dn.net/?f=%5Ctau%3D%28-2k%29%5C%20N-m)
The torque is acting in -z axis.
(a) The magnitude of torque is given by :
![|\tau|=\sqrt{(-2)^2}](https://tex.z-dn.net/?f=%7C%5Ctau%7C%3D%5Csqrt%7B%28-2%29%5E2%7D)
![|\tau|=2\ N-m](https://tex.z-dn.net/?f=%7C%5Ctau%7C%3D2%5C%20N-m)
Hence, this is the required solution.
Answer:
d) The speed of the astronaut
Explanation:
The sentence describes the speed of the astronaut. This speed value is 10meters per minute.
Now let us understand why;
- Speed is the distance divided by time. It is a scalar quantity without regard for direction but it has magnitude.
- The value 10meters per minute clearly shows this instance. We do not know the direction the astronaut is moving towards.
- Velocity, like speed is the displacement of a body with time. It is a vector quantity and it shows the direction of motion.
- For example, 10m/s due west is a velocity value because we know the direction.
Therefore, since there is no directional sense, the value indicates speed.
Answer:
.................... protons :)
Answer:37 J
Explanation:
Given
Step :1
Heat added Q=44 J
Work done=-20 J
![\Delta E_1=Q+W=44-20=24 J](https://tex.z-dn.net/?f=%5CDelta%20E_1%3DQ%2BW%3D44-20%3D24%20J)
Step :2
Heat added Q=-61 J
work done ![W_2](https://tex.z-dn.net/?f=W_2)
![\Delta E_2=Q+W_2](https://tex.z-dn.net/?f=%5CDelta%20E_2%3DQ%2BW_2)
![\Delta E_2=61+W_2](https://tex.z-dn.net/?f=%5CDelta%20E_2%3D61%2BW_2)
![\Delta E_1+\Delta E_2=0](https://tex.z-dn.net/?f=%5CDelta%20E_1%2B%5CDelta%20E_2%3D0)
as the process is cyclic
![44-20-61+W_2=0](https://tex.z-dn.net/?f=44-20-61%2BW_2%3D0)
![W_2=37 J](https://tex.z-dn.net/?f=W_2%3D37%20J)
work done in compression is 37 J