Answer:-
27.38%
Explanation:-
Molecular weight of sodium hydrogen carbonate NaHCO3
= 23 x 1 + 1 x 1 + 12 x 1 + 16 x 3
= 84 gram
Total sodium Na present in NaHCO3 = 23 x 1 = 23 gram
Percentage of sodium present=
Total sodium x 100/ (Total molecular weight)
= 23 x 100 / 84
= 27.38 %
I remember coming across this question and the options were:
KOH, HCN, NH₃, HI, Sr(OH)₂
Now, a substance with a low pH is one that dissociates completely in water to release hydrogen ions, while basic substances dissociate completely to release hydroxide ions. Therefore, in the order of increasing pH:
HI, HCN, NH₃, Sr(OH)₂, KOH
Answer:
168.812 g/mol
Explanation:
atomic mass. of Be= 9.012
atomic mass of Br= 79.90
because there is a 2 after Br you double the atomic mass
79.90(2)= 159.8
To find the molar mass add the atomic masses of each element
9.012+159.8=168.812