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snow_tiger [21]
3 years ago
10

A circular track begins at O meters and has a total distance of 100 meters. Juliet starts at the 10-meter mark while practicing

Physics
2 answers:
Thepotemich [5.8K]3 years ago
7 0

Answer:

55 meters

Explanation:

She started at the 10 meter mark, and ran 45 meters.  So her final position is:

10 m + 45 m = 55 m

She is 55 meters from the beginning of the track (the 0 meter mark).

Alja [10]3 years ago
7 0

Answer:

55 meters

Explanation:

If Juliet starts at the 10-meter mark while practicing  for a race, after running 45 meters, she is 55 meters from the beginning of the track.

10 m + 45 m = 55 m

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which has a greater kinetic energy, a bowling ball that has a mass of 5kg travelling at 6m/s, or a ship that has a mass of 12000
AVprozaik [17]

Answer:bowling ball has greater kinetic energy

Explanation:

Kinetic energy of bowling ball:

mass=m=5kg

Velocity=v=6m/s

Kinetic energy =ke

Ke=0.5 x m x v x v

Ke=0.5 x 5 x 6 x 6

Ke=90J

Kinetic energy of ship:

mass=m=120000kg

velocity=v=0.02m/s

Ke=0.5 x m x v x v

Ke=0.5 x 120000 x 0.02 x 0.02

Ke=24J

6 0
2 years ago
An element's atomic number is 71. How many protons would an atom of this element have?
vovikov84 [41]

The atom has 71 protons.

(The atomic number of a chemical element is the number of protons found in the nucleus of an atom)

hope this helps

3 0
3 years ago
A flat, 181 ‑turn, current‑carrying loop is immersed in a uniform magnetic field. The area of the loop is 4.97 cm2 and the angle
Sidana [21]

Answer:

B = 0.135T

Explanation:

To find the magnitude of the magnetic field you use the following formula, for the torque produced by a magnetic field B in a loop:

\tau=NIABsin\theta   (1)

τ: torque = 1.51*10^-5 Nm

I: current = 2.47mA = 2.47*10^-3 A

B: magnitude of the magnetic field

A: area of the loop = 4.97cm^2 = 4.97(10^-2m)^2=4.97*10^-4m^2

N: turns = 181

θ: angle between B and the magnetic dipole (same as the direction  of the normal to the plane)

You replace the values of the parameters in (1). Furthermore you do B the subject of the formula:

B=\frac{\tau}{NIAsin\tetha}=\frac{1.51*10^{-5}Nm}{(181)(2.47*10^{-3}A)(4.97*10^{-4}m^2)(sin30.1\°)}=0.135T

3 0
3 years ago
The light which allows you to see this very interesting exam is made up of waves. In these waves, the distance between crests is
lakkis [162]

Answer:

idk

Explanation:

idk

5 0
3 years ago
Read 2 more answers
A steel aircraft carrier is 403 m long when moving through the icy North Atlantic at a temperature of 1.22 °C. By how much does
Lorico [155]

Answer:

it expands by 11 cm.

Explanation:

First we need the coefficient of linear thermal expansion of steel

a = 12e-6/K

Now we use the equation for linear thermal expansion

L1 = L0 * (1 + a * (t1 - t0))

Where

L0: length before expansion

L1: expanded length

t0: temperature before expansion

t1: temperature expanded

L1 = 403 * (1 + 12e-6 * (24 - 1.22)) = 403.11 m

It expanded 11 cm.

8 0
3 years ago
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