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3 years ago

A circular track begins at O meters and has a total distance of 100 meters. Juliet starts at the 10-meter mark while practicing

Physics

2 answers:

Thepotemich [5.8K]3 years ago

7 0

Answer:

55 meters

Explanation:

She started at the 10 meter mark, and ran 45 meters. So her final position is:

10 m + 45 m = 55 m

She is 55 meters from the beginning of the track (the 0 meter mark).

Alja [10]3 years ago

7 0

Answer:

55 meters

Explanation:

If Juliet starts at the 10-meter mark while practicing for a race, after running 45 meters, she is 55 meters from the beginning of the track.

10 m + 45 m = 55 m

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Consider a plywood square mounted on an axis that is perpendicular to the plane of the square and passes through the center of t

belka [17]

Answer:

T= 8.061N*m

Explanation:

The first thing to do is assume that the force is tangential to the square, so the torque is calculated as:

T = Fr

where F is the force, r the radius.

if we need the maximum torque we need the maximum radius, it means tha the radius is going to be the edge of the square.

Then, r is the distance between the edge and the center, so using the pythagorean theorem, r i equal to:

r = $\sqrt{(0.38m)^2+(0.38m)^2}$

r = 0.5374m

Finally, replacing the value of r and F, we get that the maximun torque is:

T = 15N(0.5374m)

T= 8.061N*m

4 0

4 years ago

You can carry a 50 N weight up a flight of stairs that is 3 m high in 10 s. Then you carry 40 N up two flights of stairs in 20 s

d1i1m1o1n [39]

You can do 50 and 10 and carry the 30 and it would be in the same power so you’ll have the same energy

5 0

3 years ago

How far will a train with a speed of 20 m/s travel in: 10s

Citrus2011 [14]

Answer:

The correct answer would be 200m

Explanation:

20x10=200

the previous answer is incorect from the other user.

8 0

3 years ago

An object is projected from the ground with an upward speed of ų m/s has a speed of 23m/s when it is at a height of 5m above the

vovikov84 [41]

Answer:

25.08m/s

Explanation:

mgh1 + 0.5mv1² = mgh2 + 0.5mv2²

h1 = 0m

v1 = u

h2 = 5m

v2 = 23m/s

putting the values into the formula above;

m(10)(0) + 0.5m(u²) = m(10)(5) + 0.5m(23²)

0 + 0.5mu² = 50m + 264.5m

0.5mu² = 314.5m

dividing through by m

0.5u² = 314.5

u² = 629

u = 25.08m/s

Therefore, the initial speed "u" = 25m/s

6 0

3 years ago

4. As Juan is going to take a shower, the soap falls out of the soap dish on to the

LiRa [457]

The coefficient of friction between the soap and the floor is 0.081

If Juan steps on the soap with a force of 493 N, this is her weight, W. This weight also equals the normal reaction on the floor, N.

We know that frictional force F = μN where μ = coefficient of friction between soap and floor.

So, μ = F/N

Since F = 40 N and N = W = 493 N,

μ = F/N

μ = 40 N/493 N

μ = 0.081

So, the coefficient of friction between the soap and the floor is 0.081

Learn more about coefficient of friction here:

brainly.com/question/13923375

5 0

3 years ago