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ikadub [295]
3 years ago
9

what is newton's second law of motion? forces are balanced when they are equal and opposite. an object at rest or in motion will

remain at rest or in motion unless acted upon by an unbalanced force. the smaller the mass of an object, the greater the acceleration of that object when a force is applied. the greater the force applied, the greater the acceleration. every reaction is equal to the force applied.
Physics
2 answers:
Troyanec [42]3 years ago
6 0
The smaller the mass of an object, the greater the acceleration of that object when a force is applied because mass and acceleration are inversely related The greater the force applied, the greater the acceleration as Force and acceleration are directly related quantities.
sleet_krkn [62]3 years ago
5 0

Answer:

B

Explanation:

The Newton's second Law of motion states that:

- An object at rest or in motion will remain at rest or in motion unless acted upon by an unbalanced force.

- The expression is given by:

                                   F_net = m*a

- If F_net  = 0, then a = 0.

- However, if a = 0, not always is velocity is zero but the change in velocity is.

Hence, the object in motions travels with a constant velocity even if all the forces are balanced or no net force is present.

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This is the third time I’m asking, please, On a wet road, is a higher coefficient of friction on the tires safer or a lower one
jenyasd209 [6]

Answer:

higher is safer

Explanation:

because it is a wet slippery surface, you would need more friction on the tires, to get more traction in the slippery wet road, if you had low friction you would not move anywhere and or could swerve off somewhere

4 0
1 year ago
Two positive charges of 6.0 x 10^-6 C are separated by 0.50 m. Calculate the force of electrical attraction
SpyIntel [72]

Answer:

Force between two charges is given as 1.296 N

Explanation:

As we know that the two charges will attract or repel each other when they are placed near to each other

Here we know that electrostatic force is given as

F = \frac{kq_1 q_2}{r^2}

here we have

q_1 = q_2 = 6 \times 10^{-6} C

distance between two charges is given as

r = 0.50 m

so we have

F = \frac{(9\times 10^9)(6 \times 10^{-6})^2}{0.50^2}

F = 1.296 N

3 0
3 years ago
What is the threshold velocity vthreshold(water) (i.e., the minimum velocity) for creating Cherenkov light from a charged partic
VladimirAG [237]

Complete Question

The  complete question is shown on the first uploaded image  

Answer:

A

   v_w  =  2.256 *10^{8} \  m/s

B

  v_e  =  2.21 *10^{8} \  m/s

C

The  correct option is  B  

Explanation:

From the question we are told that

      The refractive  index of water is  n_w  =  1.33

      The  refractive  index of ethanol is  n_e  =  1.36

       

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

       v_w  =  \frac{c}{n_w }

Where  c is the speed of light with value  c =  3.0 *10^{8} \  m/s

       v_w  =  \frac{3.0 *10^{8}}{1.33 }

       v_w  =  2.256 *10^{8} \  m/s

Generally the threshold velocity for creating Cherenkov light   from a charged particle as it travels through water is mathematically evaluated as

            v_e  =  \frac{ c}{n_e }

  =>       v_e  =  \frac{3.0 *10^{8}}{1.36 }

=>          v_e  =  2.21 *10^{8} \  m/s

4 0
3 years ago
Will give brainliest! A team of engineers is asked to evaluate several different
Levart [38]

Answer:

the answer if im not mistaken is A

Hope this helps:)

6 0
3 years ago
A ship's wheel has a moment of inertia of 0.930 kilogram·meters squared. The inner radius of the ring is 26 centimeters, and the
Vikki [24]

We can use the formula of the moment of inertia given by:

r\cdot F=I\alpha

Where:

r = Distance from the point about which the torque is being measured to the point where the force is applied

F = Force

I = Moment of inertia

α = Angular acceleration

So:

\begin{gathered} r\cdot F=(-0.26\times314+290\times0.32)=92.8-81.64=11.16 \\ I=0.930 \\ so,_{\text{ }}solve_{\text{ }}for_{\text{ }}\alpha: \\ \alpha=\frac{r\cdot F}{I} \\ \alpha=\frac{11.16}{0.930} \\ \alpha=\frac{12rad}{s^2} \end{gathered}

Answer:

12 rad/s²

8 0
1 year ago
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