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ikadub [295]
3 years ago
9

what is newton's second law of motion? forces are balanced when they are equal and opposite. an object at rest or in motion will

remain at rest or in motion unless acted upon by an unbalanced force. the smaller the mass of an object, the greater the acceleration of that object when a force is applied. the greater the force applied, the greater the acceleration. every reaction is equal to the force applied.
Physics
2 answers:
Troyanec [42]3 years ago
6 0
The smaller the mass of an object, the greater the acceleration of that object when a force is applied because mass and acceleration are inversely related The greater the force applied, the greater the acceleration as Force and acceleration are directly related quantities.
sleet_krkn [62]3 years ago
5 0

Answer:

B

Explanation:

The Newton's second Law of motion states that:

- An object at rest or in motion will remain at rest or in motion unless acted upon by an unbalanced force.

- The expression is given by:

                                   F_net = m*a

- If F_net  = 0, then a = 0.

- However, if a = 0, not always is velocity is zero but the change in velocity is.

Hence, the object in motions travels with a constant velocity even if all the forces are balanced or no net force is present.

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A 12.0-g bullet is fired horizontally into a 109-g wooden block that is initially at rest on a frictionless horizontal surface a
kykrilka [37]

Answer:

v₀ = 280.6 m / s

Explanation:

we have the shock between the bullet and the block that we can work with at the moment and another part where the assembly (bullet + block) compresses a spring, which we can work with mechanical energy,

We write the mechanical energy when the shock has passed the bodies

   Em₀ = K = ½ (m + M) v²

We write the mechanical energy when the spring is in maximum compression

Em_{f} = K_{e} \\= \frac{1}{2} kx^2\\    Em_0 = Em_{f}

½ (m + M) v² = ½ k x²

Let's calculate the system speed

   v = √ [k x² / (m + M)]

   v = √[152 ×0.78² / (0.012 +0.109) ]

   v = 27.65 m / s

This is the speed of the bullet + Block system

Now let's use the moment to solve the shock

Before the crash

   p₀ = m v₀

After the crash

p_{f} = (m + M) v

The system is formed by the bullet and block assembly, so the forces during the crash are internal and the moment is preserved

 p_0 =  p_{f}

  m v₀ = (m + M) v

  v₀ = v (m + M) / m

let's calculate

v₀ = 27.83 (0.012 +0.109) /0.012

  v₀ = 280.6 m / s

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