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3 years ago

6

A sumo wrestler pushes another sumo wrestler back 3.41 meters, with a force of 120 N. How much work did he do? Round your answer

to 2 decimal places.

1 answer:

ser-zykov [4K]3 years ago

4 0

Answer:

work=force* distance

Explanation:

cal it your self

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Greyhound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but

maw [93]

${\large{\bold{\rm{\underline{Given \; that}}}}}$

★ A grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.

${\large{\bold{\rm{\underline{To\; find}}}}}$

★ The speed of the hound and the hare

${\large{\bold{\rm{\underline{Solution}}}}}$

★ The speed of the hound and the hare = 25:18

${\large{\bold{\rm{\underline{Full \; Solution}}}}}$

$\dashrightarrow$ As it's given that a grey hound pursues a hare and takes 5 leaps for every 6 leaps of the hare, but 3 leaps of the hound are equal to 5 leaps of the hare.

So firstly let us assume a metres as the distance covered by the hare in one leap.

Ok now let's talk about 5 leaps,.! As it's cleared that the hare cover the distance of 5a metres.

But 3 leaps of the hound are equal to 5 leaps of the hare.

Henceforth, (5/3)a meters is the distance that is covered by the hound.

Now according to the question,

Hound pursues a hare and takes 5 leaps for every 6 leaps of the hare..! (Same interval)

Now the distance travelled by the hound in it's 5 leaps..!

(5/3)a × 5

25/3a metres

Now the distance travelled by the hare in it's 6 leaps..!

6a metres

Now let us compare the speed of the hound and the hare. Let us calculate them in the form of ratio..!

25/3a = 6a

25/3 = 6

25:18

5 0

3 years ago

A can of soup is begin heated in a sauce pan. as the soup is heated, the warm fluid becomes less dense and rises, while the cool

Alexxandr [17]

It is c convection because convection is when something is hot therefore less dense material to rise and cooler material to sink under the influence of gravity

8 0

3 years ago

Two sticks are suspended on silk thread, electrified by charges of opposite sign. Is there a magnetic field around them? An elec

IRINA_888 [86]

ANSWER and EXPLANATION

We want to identify if there will be an electric field and a magnetic field around the two sticks electrified by charges of opposite signs.

An electric field is a physical field that surrounds electrically charged particles and exerts a force on other charged particles in the surrounding.

This implies that the presence of electric charges on both sticks generates electric fields on them. Since the two charges are opposite, the electric force acting on them will be attractive.

Hence, there is an electric field.

A stationary charged object produces an electric field, as explained above, but will only produce a magnetic field if there is a motion of the object.

Hence, except the two sticks are caused to move, there will be no magnetic field around them.

5 0

1 year ago

If the initial velocity of a ball is sent straight upward at 10.5m/s from the ground what will its final velocity be when it hit

Shalnov [3]

Answer: -10.08 m/s

Explanation:

Here we only need to analyze the vertical problem.

When the ball is in the air, the only force acting on it will be the gravitational force, this means that the acceleration of the ball, is equal to the gravitational acceleration, then:

a(t) = -9.8m/s^2

Where the negative sign is because gravity pulls the ball down.

To get the velocity equation we need to integrate over time, we get:

v(t) = (-9.8m/s^2)*t + v0

Where v0 is the initial vertical velocity, here it is v0 = 10.5 m/s

Then the velocity equation is:

v(t) = (-9.8m/s^2)*t + 10.5 m/s

To get the position equation, we need to integrate again over time, we get:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t + p0

Where p0 is the initial position, we know that the ball is sent upward from the ground, so p0 = 0m

Then the position equation is:

p(t) = (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t

Now we need to find the value of t such that the position is equal to zero (this means that the ball hits the ground again).

Then we need to solve:

p(t) = 0 = (1/2)*(-9.8m/s^2)*t^2 + (10.5 m/s)*t

If we divide both sides by t, we get:

0 = (1/2)*(-9.8m/s^2)*t + (10.5 m/s)

Now we can solve it:

(1/2)*(9.8m/s^2)*t = 10.5 m/s

t = (10.5 m/s)/((1/2)*(9.8m/s^2)) = 2.14 s

This means that after 2.14 seconds, the ball will hit the ground again.

The velocity of the ball when it hits the ground is equal to:

v(2.14s) = (-9.8m/s^2)*2.14s + 10.5 m/s = -10.08 m/s

3 0

3 years ago

Two rocks are moving through empty space in a straight line at the same speed. One has a mass of 10 kg, the other has a mass of

Yuki888 [10]

A and D are definitely wrong because the two rocks have different masses, so it leaves us with B and C. The most logical answer to the question is
C <span>The one with greater mass takes more force to stop.
</span>

6 0

3 years ago