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Anit [1.1K]
3 years ago
8

Fill in the blanks. The celestial bodies in space move about in predictable paths called

Chemistry
2 answers:
ella [17]3 years ago
7 0

Answer:

Magnetic fields, revolve, asteroids

butalik [34]3 years ago
5 0
The celestial bodies in space move about in predictable paths called ORBITS. As a result, a planet is able to REVOLVE around the Sun. Other objects in the solar system, also orbit the Sun. These objects include ASTEROIDS and comets.
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Ideal He gas expanded at constant pressure of 3 atm until its volume was increased from 9 liters to 15 liters. During this proce
kkurt [141]

Explanation:

The given data is as follows.

             P = 3 atm

                = 3 atm \times \frac{1.01325 \times 10^{5} Pa}{1 atm}  

                 = 3.03975 \times 10^{5} Pa

    V_{1} = 9 L = 9 \times 10^{-3} m^{3}    (as 1 L = 0.001 m^{3}),  

        V_{2} = 15 L = 15 \times 10^{-3} m^{3}

            Heat energy = 800 J

As relation between work, pressure and change in volume is as follows.

                  W = P \times \Delta V

or,                W = P \times (V_{2} - V_{1})

Therefore, putting the given values into the above formula as follows.

                  W = P \times (V_{2} - V_{1})

                      = 3.03975 \times 10^{5} Pa \times (15 \times 10^{-3} m^{3} - 9 \times 10^{-3} m^{3})

                      = 1823.85 Nm

or,                   = 1823.85 J

As internal energy of the gas \Delta E is as follows.

                     \Delta E = Q - W

                                  = 800 J - 1823.85 J

                                  = -1023.85 J

Thus, we can conclude that the internal energy change of the given gas is -1023.85 J.

8 0
3 years ago
A buffer solution is composed of 7.50 mol of acid and 4.75 mol of the conjugate base. If the pKa of the acid is 4.90 , what is t
Mamont248 [21]

Answer:

The correct answer is: pH= 4.70

Explanation:

We use the <em>Henderson-Hasselbach equation</em> in order to calculate the pH of a buffer solution:

pH= pKa + log   \frac{ [conjugate base]}{[acid]}

Given:

pKa= 4.90

[conjugate base]= 4.75 mol

[acid]= 7.50 mol

We calculate pH as follows:

pH = 4.90 + log (4.75 mol/7.50 mol) = 4.90 + (-0.20) = 4.70

7 0
2 years ago
A sample of gas at 47C and 1.5 pressure occupies a volume of 2.20L. What volume would this gas occupy at 107C and 2.5 pressure?
Brums [2.3K]

Answer:

Explanation:

21

8 0
3 years ago
25.4 g of salt was dissolved in distilled water to make 425 mL of solution.
ladessa [460]
Use 25.4 g/ 425ml x 100 5.94 percent
3 0
3 years ago
3O2(g) 2O3(g); Keq = 1
Marta_Voda [28]
The first one is correct ! by mass law ,

(O2)3÷(O3)2= keq
as keq = 1

thus both are equal and so answer is 1 !
6 0
3 years ago
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