Question

Two ice skaters suddenly push off against one another starting from a stationary position. The 50 kg skater acquires a speed of 0.3 m/s relative to the ice. What speed does the 60 kg skater acquire relative to the ice

Answer 1

Answer:

$V_{22}=0.25m/s$

Explanation:

From the question we are told that:

Mass 1 $M_1=50kg$

Speed 1 $V_1=0.3m/s$

Mass 2 $M_2=60kg$

Generally the equation for momentum is mathematically given by

 $M_1V_{11}+m_2V_{21}=M_1V_{12}+m_2V_{22}$

Where

 $v_{11}=v_{21}=0$

Therefore

 $M_1V_12-M_2V_22$

 $V_{22}=\frac{m_1v22}{m_2}$

 $V_{22}=\frac{m_1V_22}{m2}$

 $V_{22}=\frac{50*0.3}{60}$

 $V_{22}=0.25m/s$