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3 years ago

A molecule of butane and a molecule of 2-butene both have the same total number of

2 answers:

8 0

1) same amount of carbon atoms.

That is why it is still called butane and butene.
but- always signifies 4 carbons

dolphi86 [110]3 years ago

7 0

Answer: Option (1) is the correct answer.

Explanation:

A hydrocarbon that contains only single bonds is known as alkane. Their general formula is $C_{n}H_{2n+2}$ , where n is the number of carbon atoms.

For example, butane ( $CH_{3}CH_{2}CH_{2}CH_{3}$ ) is an alkane.

Whereas a hydrocarbon that contains at least one double bond is known as an alkene. Their general formula is $C_{n}H_{2n}$ .

For example, 2-butene ( $CH_{3}CH=CHCH_{3}$ ) is an alkene.

Hence, there are same number of carbon atoms in both butane and 2-butene.

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What is the chemical formula of the following compound

OLga [1]

A. C3H10 is the answer

6 0

2 years ago

Titanium has an HCP crystal structure, a c/a ratio of 1.669, an atomic weight of 47.87 g/mol, and a density of 4.51 g/cm3. Compu

IrinaK [193]

Answer : The atomic radius for Ti is, $1.45\times 10^{-8}cm$

Explanation :

Atomic weight = 47.87 g/mole

Avogadro's number $(N_{A})=6.022\times 10^{23} mol^{-1}$

First we have to calculate the volume of HCP crystal structure.

Formula used :

$\rho=\frac{Z\times M}{N_{A}\times V}$ .............(1)

where,

$\rho$ = density = $4.51g/cm^3$

Z = number of atom in unit cell (for HCP = 6)

M = atomic mass = 47.87 g/mole

$(N_{A})$ = Avogadro's number

V = volume of HCP crystal structure = ?

Now put all the values in above formula (1), we get

$4.51g/cm^3=\frac{6\times (47.87g/mol)}{(6.022\times 10^{23}mol^{-1}) \times V}$

$V=1.06\times 10^{-22}cm^3$

Now we have to calculate the atomic radius for Ti.

Formula used :

$V=6R^2c\sqrt{3}$

Given:

c/a ratio = 1.669 that means, c = 1.669 a

Now put (c = 1.669 a) and (a = 2R) in this formula, we get:

$V=6R^2\times (1.669a)\sqrt{3}$

$V=6R^2\times (1.669\times 2R)\sqrt{3}$

$V=(1.669)\times (12\sqrt{3})R^3$

Now put all the given values in this formula, we get:

$1.06\times 10^{-22}cm^3=(1.669)\times (12\sqrt{3})R^3$

$R=1.45\times 10^{-8}cm$

Therefore, the atomic radius for Ti is, $1.45\times 10^{-8}cm$

3 0

2 years ago

If the dimensions of a cube-shaped cell with a volume of 1 pm were to

melamori03 [73]

Answer:

Explanation:

Assuming the units are all supposed to be the same

A cube shaped cell with a 1 um³ volume would have a dimensions of 1 x 1 x 1 (because volume = length x width x height and 1 x 1 x 1 =1)

If we double the dimensions, we have a cube with the dimensions 2 x 2 x 2.

The surface area of each face of the cube is the length x width, so 2 x 2. This means the surface area of each face of the cube is 4 um².

There are 6 faces of a cube, so the total surface area is 6 x 4 um² = 24 um².

5 0

2 years ago

What happens when a condition of metal oxide is tested with (i)blue litmus (ii)red litmus

Artemon [7]

it has no effect on the blue litmus.

When it's tested on the red litmus paper it turns blue

7 0

3 years ago

(PLEASE ANSWER + BRAINLIEST !!)

MatroZZZ [7]

A gamma ray has a mass and atomic number of 0 meaning it doesn’t effect the nucleus.
E.g
60 60 0
Co —> Co + gamma ray
27 27 0

7 0

2 years ago