Answer:
0.50 M
Explanation:
Given data
- Mass of sodium sulfate (solute): 7.1 g
- Volume of solution: 100 mL
Step 1: Calculate the moles of the solute
The molar mass of sodium sulfate is 142.04 g/mol. The moles corresponding to 7.1 grams of sodium sulfate are:

Step 2: Convert the volume of solution to liters
We will use the relation 1 L = 1000 mL.

Step 3: Calculate the molarity of the solution

Magnet to remove the iron, filter paper (or some filter that could trap sand) to remove the sand, and heat up the salt and water, causing the water to evaporate to separate them.
Acid base neutralization reaction is a chemical reaction between acid and base, which will result into water and a salt. this is neutralization because the product of the reaction which is water is neutral, the pH is 7 and the salt as well
2 C2H6 + 7 O2 -> 4CO2 + 6 H2O
<span>so the products are carbondioxide & water vapour</span>