Answer:
The value of acceleration due to gravity is independent of mass of the body.
Explanation:
Let us consider the mass of the object as m and mass of earth as M
Therefore, force between the object and earth would be given by: F = GMm/d²
This force is equal to the weight of the object, i.e. mg
Thus;
mg = GMm/d²
g = GM/d²
Therefore, the value of acceleration due to gravity is independent of mass of the body.
Answer:
The neutral wire and the ground wire.
Explanation:
The black wire is the hot wire
The neutral wire provides the return path for the current provided by the hot wire.
The ground wire is connected to any metal parts in an appliance for example microwave.
A standard electrical outlet has three wires connected to it: the hot, the neutral, and the ground. There is no potential difference between the neutral wire and the ground wire.
Answer:
Va = 5000 m / 3600 s = 1.39 m/s
(Va - Vb) 60 = 10
Vb = Va - .167 = 1.22 m/s
(Va - Vb) T = 4200 Π where T is time for A to complete 1 more lap
.17 T = 4200 Π
T = 24700 Π time for A to again catch B
N = 1.39 * 24700 Answer:
Va = 5000 m / 3600 s = 1.39 m/s
(Va - Vb) 60 = 10
Vb = Va - .167 = 1.22 m/s
(Va - Vb) T = 4200 Π where T is time for A to complete 1 more lap
.17 T = 4200 Π
T = 24700 Π time for A to again catch B
N = 1.39 * 24700 Π / (4200 Π) = 8.2 laps
A will make 8 but not 9 rounds before catching B
When a car maintains a velocity of exactly 65 mph, it's acceleration is zero.
<h3>What is acceleration?</h3>
The acceleration is time rate of change of velocity.
When the velocity is not changing with respect to time, it is said to be an object moving with constant velocity.
At constant velocity, there is no acceleration.
Thus, when a car maintains a velocity of exactly 65 mph, it's acceleration is zero.
Learn more about acceleration.
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If voltage is doubled<span> then let the new </span>voltage<span> be such that . ... Thus, the </span>current<span> flowing </span>through<span>the </span>circuit<span> will be </span>doubled<span> if </span>voltage<span> applied across the </span>circuit<span> is </span>doubled<span>.</span>
