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skelet666 [1.2K]
3 years ago
5

Average velocity is different than average speed because calculating average velocity involves ?

Physics
2 answers:
ch4aika [34]3 years ago
7 0

Average velocity is different than average speed because calculating average velocity involves direction.

Answer: Direction

Explanation

Average speed involves taking only the magnitude in the calculation of the distance traveled and the time required whereas Average velocity takes both magnitude and direction in the calculation by taking the displacement occurred with total time.

Therefore, average speed, scalar quantity and average velocity, a vector quantity.

Scalar quantities are physical quantities considering magnitude whereas vector quantities are physical quantities considering magnitude and direction.

Studentka2010 [4]3 years ago
5 0
Direction!

Velocity is a vector quantity and speed is a scalar quantity. Vector quantities includes both magnitude and direction, while scalar quantities only have magnitude. :)
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Thats her fault.........................b

Explanation:

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3 years ago
5. A construction worker on a high-rise building is on a platform suspended between two cables as illustrated below. The constru
Natalka [10]

Answer:

a) Tc = 750 [N]  ;b) See the explanation below.

Explanation:

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b)

The solution of this type of problem corresponds to the use of Newton's third law, applying static which tells us that the sum of the forces in a system in equilibrium without movement must be equal to zero.

a)

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4 0
3 years ago
A wire with a circular cross section and a resistance R is lengthened to 9.66 times its original length by pulling it through a
damaskus [11]

Answer:

The resistance of the wire after it is stretched is 93.31R.

Explanation:

Resistance is the property of the material to oppose the current flow through it. It is given by the relation :

R = (ρl)/A

Here ρ is resistivity, l is length of wire and A is the area of the wire.

Let l₀, and A₀ are the original length and original circular cross section area of the wire. while l₁ and A₁ are the new length and new circular cross section area of the wire.

Volume of the original wire, V₀ = A₀ x l₀

Volume of the new wire, V₁ = A₁ x l₁

According to the problem. volume remain same. So,

V₀ = V₁

A₀ x l₀ = A₁ x l₁

It is given that l₁ = 9.66 x l₀. Substitute this value in the above equation;

A₀ x l₀ = A₁ x 9.66 x l₀

A₁ = A₀/9.66

Resistance of the original wire, R = (ρl₀)/A₀

Resistance of the new wire, R₁ = (ρl₁)/A₁

Substitute the value of l₁ and A₁ in the above equation.

R₁ = (ρ x l₀ x 9.66)/(A₀/9.66) = 93.31 x (ρl₀)/A₀

But (ρl₀)/A₀ = R. hence,

R₁ = 93.31 R

8 0
3 years ago
. A spring has a length of 0.200 m when a 0.300-kg mass hangs from it, and a length of 0.750 m when a 1.95-kg mass hangs from it
kap26 [50]

Answer:

29.4 N/m

0.1  

Explanation:

a) From the restoring Force we know that :  

F_r = —k*x  

the gravitational force :  

F_g=mg  

Where:

F_r is the restoring force .

F_g is the gravitational force

g is the acceleration of gravity

k is the constant force  

xi , x2 are the displacement made by the two masses.

Givens:

<em>m1 = 1.29 kg</em>

<em>m2 = 0.3 kg  </em>

<em>x1   = -0.75 m  </em>

<em>x2 = -0.2 m </em>

<em>g   = 9.8 m/s^2  </em>

Plugging known information to get :

F_r =F_g

-k*x1 + k*x2=m1*g-m2*g

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b) To get the unloaded length 1:  

l=x1-(F_1/k)

Givens:

m1 = 1.95kg , x1 = —0.75m  

Plugging known infromation to get :

l= x1 — (F_1/k)  

= 0.1  

 

3 0
3 years ago
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timofeeve [1]

Answer:

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7 0
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