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3 years ago

Solve 3x(4x+5)=33 you may use the flowchart if u wish

Mathematics

1 answer:

Dvinal [7]3 years ago

4 0

The full answer with choices

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I NEED HELP PLEASEEE ASAP

nikklg [1K]

2) x= -8
3) y= -3
4) c= -2

8 0

3 years ago

Find the amount of money in an account after 4 years if $1800 is deposited at 5% annual interest compounded quarterly.

strojnjashka [21]

Answer:

$2195.80

Step-by-step explanation:

For a initial principal, P compounded with period k over n years at an annual interest rate, r, the amount (A(n)) at the end of n years is determined using the function:

$A(n)=P(1+\frac{r}{k})^{nk}$

In the given case:

P=$1800

n=4 years

r=5%=0.05

Since it is compounded quarterly, Period, k=4

Therefore, the amount of money in the account after 4 years is:

$A(n)=1800(1+\frac{0.05}{4})^{4*4}\\=1800(1+0.0125)^{16}\\=1800(1.0125)^{16}\\=\$2195.80$

After 4 years, there will be $2195.80 in the account.

8 0

4 years ago

In triangle ABC, the size of the B is 4 times the size of angle A, and the size of angle C is 14 cel less than 5 times the size

Neporo4naja [7]

Answer:

$A = 19.4$

$B = 77.6$

$C =83$

Step-by-step explanation:

Given

By interpreting each line, we have:

$B = 4A$

$C = 5A -14$

Required

Solve for A, B and C

In a triangle,

$A + B + C = 180$

Substitute expressions for B and C

$A + 4A + 5A - 14 = 180$

$A + 4A + 5A = 180+14$

$10A = 194$

Solve for A

$A = 194/10$

$A = 19.4$

$B = 4A$

$B = 4 * 19.4$

$B = 77.6$

$C = 5A -14$

$C =5 * 19.4 - 14$

$C =83$

5 0

3 years ago

Help me please !! 2b + 1 b=___

HACTEHA [7]

Answer: Cannot factor

Step-by-step explanation:

8 0

3 years ago

Among a group of 60 engineering students, 24 take math and 29 take physics. Also 10 take both physics and statistics, 13 take bo

ivolga24 [154]

Answer:

a) 26

b) 0.3076

Step-by-step explanation:

We are given the following in the question:

M: Math

P: Physics

S: Statistic

n(Math) = 24

n(Physics) = 29

$n(P\cap S) = 10$

$n(M\cap P) = 13$

$n(M\cap S) = 11$

$n(M\cap P\cap S) = 8$

$n(M'\cap P'\cap S') = 7$

a) Number of students who take statistics

Formula:

$n(P\cup M\cup S)=\\n(P)+n(M)+n(S)-n(P\cap M)-n(P\cap S)-n(M\cap S)+n(P\cap M\cap S)$

Putting the values, we get,

$n(P\cup M\cup S) = n - n(P'\cap M'\cap S') = 60-7 = 53$

$53 = 24 + 29 + n(S) -10-13-11+8\\n(S) = 53-24-29+10+13+11-8\\n(S) = 26$

Thus, 26 students took statistic.

b) probability that a student selected at random takes all three, given he takes statistics

$p(\text{All three subject}|\text{Statistic})\\\\=\displaystyle\frac{n(P\cap M\cap S)\cap n(S)}{n(S)}\\\\= \frac{8}{26} = 0.3076$

8 0

3 years ago