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yKpoI14uk [10]
3 years ago
14

Put in order please!!!!!! PLEASE!!!!!!!!!!!!!!!!!!!!

Chemistry
2 answers:
GuDViN [60]3 years ago
8 0
A. Groundwater
B. transpiration
C. Condensation
D. Interception
E. Infiltration
F. Evaporation
kondor19780726 [428]3 years ago
8 0
Its already in alphabetical order
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The equation below represents the chemical reaction between the elements hydrogen and oxygen when the compound water is formed.
olga2289 [7]

Answer:

b

Explanation:

. B. atoms of the elements hydrogen and oxygen are in the reactants and also in the productsatoms of the elements

7 0
2 years ago
Which represents the overall (net) reaction of this mechanism: step 1: H2O2 + I- → H2O + OI- step 2: H2O2 + OI- → H2O + O2 + I-
11111nata11111 [884]

Answer:

A. 2H₂O₂  → 2H₂O + O₂

Explanation:

  • 1. H₂O₂ + I⁻ → H₂O + OI⁻
  • 2. H₂O₂ + OI⁻ → H₂O + O₂ + I⁻

If we <u>make a net sum of both reactions</u>, we're left with:

  • H₂O₂ + I⁻ + H₂O₂ + OI⁻ → H₂O + OI⁻ + H₂O + O₂ + I⁻

Grouping species:

  • 2H₂O₂ + OI⁻ + I⁻ → 2H₂O + OI⁻ + O₂ + I⁻

There is OI⁻ at both sides, so it is eliminated -same goes for the catalyst, I⁻-.

  • 2H₂O₂  → 2H₂O + O₂

Thus the answer is option A.

4 0
3 years ago
When oxygen reacts with hydrogen, it has the capacity to release 29 kilojoules of energy. Inside a fuel cell, oxygen reacts with
Vanyuwa [196]

Answer:

79

Explanation:

7 0
3 years ago
What quality is attributed to water due to “capillary action”?
irakobra [83]

Answer:

I think it's B. The ability of water molecules to adhere to the surfaces of objects

4 0
3 years ago
When an electron in a 2p orbital of a particular atom makes a transition to the 2s orbital, a photon of approximate wavelength 6
Mariulka [41]

Answer:

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

Explanation:

Wavelength of the photon emitted = \lambda =646.3 nm =646.3\times 10^{-9} m

Energy of the photon will corresponds to the energy difference between 2p and 2s orbital = E

Energy of the photon is given by Planck's equation:

E=\frac{hc}{\lambda }

h = Planck's constant = 6.626\tiomes 10^{-34} Js

c = Speed of the light = 3\times 10^8 m/s

E=\frac{6.626\tiomes 10^{-34} Js\times 3\times 10^8 m/s}{646.3\times 10^{-9} m}

E=3.07\times 10^{-19} J

The energy difference between these 2p and 2s orbitals is 3.07\times 10^{-19} J

3 0
3 years ago
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