Answer:
41.7feet
Step-by-step explanation:
From the question we are given the following
angle of depression = 50°
Distance of the pole from the base of the feet = 35feet (Adjacent)
Required
height of the school (opposite)
Using the SOH CAH TOA identity
Tan theta = opp/adj
Tan 50 = H/35
H = 35tan 50
H = 35(1.1918)
H = 41.7feet
Hence the height of the school is 41.7feet
Can you help me please I need help with a couple of questions
Answer:
Step-by-step explanation:
hello :
3b^4−6b^2+27b = 3b(b^3-2b+9)
Answer:
Step-by-step explanation:
Final Answer: 19.5%
Answer:
a. (5x-2)-(2x+1)
b. 3x-3
c.39
Step-by-step explanation: