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Dmitriy789 [7]
3 years ago
15

Draw triangle WAK with a K= 12 KW= 15 and WA= 10. List the angles in order from largest to smallest

Mathematics
1 answer:
butalik [34]3 years ago
3 0

Answer:

probably KW WA And K

Step-by-step explanation:

btw nice L profile picture love deathnote

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PLEASE HELP WITHIN 5 MINUTES! Be as accurate as possible!
Nookie1986 [14]

Answer:

2,75in

4,25in

33in²

Step-by-step explanation:

shorter base is 2,75in

larger base is 4,25in

S=11+10,5+9+2,5=33in²

8 0
3 years ago
What are the next 3 terms of the following sequence?<br> 3, -1, -5, -9
MA_775_DIABLO [31]

Answer: -13, -17, -21

Explanation: Subtract 4 from each term. Do this for 3 terms

6 0
3 years ago
Pls answer given from the graph for 50 points!
Norma-Jean [14]

Answer:

Step-by-step explanation:

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c.  Salary of L60,000/year.

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5 0
2 years ago
Find the lengths and slopes of the diagonals to name the parallelogram. Choose the most specific name. E (-2, -4), F(0, -1), G(-
Kay [80]

Answer:

1) d) Square

2) Proofs that PWRS is a rhombus are

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Step-by-step explanation:

The given points (x, y) of the parallelogram are;

E(-2, -4), F(0, -1), G(-3, 1), H(-5, -2)

The slope, m, of the segments are found as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

By computation, the slope of segment EF = 1.5

The slope of segment FG = -0.67

The slope of segment GH = 1.5

The slope of segment HE = -0.67

Therefore, EF is parallel to GH and FG is parallel to HE

The length of the sides are;

\sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

By computation, the length of segment EF = 3.61

The length of segment FG = 3.61

The length of segment GH = 3.61

The length of segment HE = 3.61

The diagonals are;

EG and FH

The length of segment EG = 5.099

The length of segment FH = 5.099

Therefore, the diagonals are equal and the parallelogram is a square

2) The given dimensions are;

P(-1, 3), Q(-2, 5), R(0, 4), S(1, 2)

A rhombus has all sides equal

The length of segment PQ = 2.24

The length of segment QR = 2.24

The length of segment RS = 2.24

The length of segment PS = 2.24

The diagonals are;

QS and PR

The length of segment QS = 4.24

The length of segment PR = 1.41

The slope of segment QR = -0.5

The slope of segment PS = -0.5

The slope of segment RS = -2

The slope of segment QP = -2

Therefore, QS≠QR the parallelogram is a rhombus

The correct option ;

Length of QS ≠ PR and

Slope of segment QR and PS is -1/2 and Slope of segment RS and QP is -2.

Where there are acute angles in parallelogram PQRS, then the correct option is d) Length of QR and PS is 2.2 and Length of RS and QP is 2.2

8 0
3 years ago
4 more than the quotient 12 and a number x
snow_tiger [21]

More than means to add.

Quotient means to divide.

4 + (12/x)

6 0
3 years ago
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