Vector A and B are given as follows:
1 answer:
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Answer:
a) P = 44850 N
b)
Explanation:
Given:
Cross-section area of the specimen, A = 130 mm² = 0.00013 m²
stress, σ = 345 MPa = 345 × 10⁶ Pa
Modulus of elasticity, E = 103 GPa = 103 × 10⁹ Pa
Initial length, L = 76 mm = 0.076 m
a) The stress is given as:
on substituting the values, we get
or
Load, P = 44850 N
Hence<u> the maximum load that can be applied is 44850 N = 44.85 KN</u>
b)The deformation () due to an axial load is given as:
on substituting the values, we get
or
Answer:
1960.32306 kg/s
Explanation:
m = Mass of water = 1 kg
g = Acceleration due to gravity = 9.81 m/s²
h = Height from which the water will fall
Potential Energy
One megawatts of power is required
So, flow rate
1960.32306 kg/s is required to produce a megawatt of power