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3 years ago

Calculate the kinetic energy of a 790-kg roller coaster traveling at a velocity of 20.7 m/s.

Physics

2 answers:

Shtirlitz [24]3 years ago

5 0

Answer:

$\displaystyle KE = 169254 \ J$

General Formulas and Concepts:

Energy

Kinetic Energy Formula: $\displaystyle KE = \frac{1}{2}mv^2$

KE is kinetic energy (in J)
m is mass (in kg)
v is velocity (in m/s)

Explanation:

Step 1: Define

[Given] m = 790 kg

[Given] v = 20.7 m/s

Step 2: Solve

Substitute in variables [Kinetic Energy Formula]: $\displaystyle KE = \frac{1}{2}(790 \ kg)(20.7 \ m/s)^2$
[KE] Evaluate exponents: $\displaystyle KE = \frac{1}{2}(790 \ kg)(428.49 \ m^2/s^2)$
[KE] Multiply: $\displaystyle KE = (395 \ kg)(428.49 \ m^2/s^2)$
[KE] Multiply: $\displaystyle KE = 169254 \ J$

Leya [2.2K]3 years ago

3 0

Answer:

The answer is 169253.55 joules

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3 years ago

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3 years ago

Infrared waves from the sun are what make our skin feel warm on a sunny day. If an infrared wave has a frequency of 3.0 x 1012 H

djyliett [7]

Answer:

The wavelength of the infrared wave is 0.0001 m.

Explanation:

Given:

Frequency of an infrared wave is, $f=3.0\times 10^{12}\ Hz$

We know that, infrared waves are electromagnetic waves. All electromagnetic waves travel with the same speed and their magnitude is equal to the speed of light in air.

So, speed of infrared waves coming from the Sun travels with the speed of light and thus its magnitude is given as:

$v=c=3.0\times 10^8\ m/s$

Where, 'v' is the speed of infrared waves and 'c' is the speed of light.

Now, we have a formula for the speed of any wave and is given as:

$v=f\lambda$

Where, $\lambda \to \textrm{Wavelength of infrared wave}$

Now, rewriting the above formula in terms of wavelength, $\lambda$ , we get:

$\lambda=\dfrac{v}{f}$

Now, plug in $3.0\times 10^8$ for 'v', $3.0\times 10^{12}$ for 'f' and solve for $\lambda$ . This gives,

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3 years ago

A spherical asteroid of average density would have a mass of 8.7×1013kg if its radius were 2.0 km.A)If you and your spacesuit ha

WITCHER [35]

A) 0.189 N

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$F=\frac{GMm}{R^2}$

where

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m = 130 kg is the mass of the man

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Substituting into the equation, we find

$F=\frac{(6.67\cdot 10^{-11})(8.7\cdot 10^{13} kg)(130 kg)}{(2000 m)^2}0.189 N=$

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where

v is the speed of the astronaut

Solving the formula for v, we find the minimum speed at which the astronaut should launch himself and then orbit the asteroid just above the surface:

$v=\sqrt{\frac{2GM}{R}}=\sqrt{\frac{2(6.67\cdot 10^{-11})(8.7\cdot 10^{13} kg)}{2000 m}}=2.41 m/s$

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3 years ago