All categories

3 years ago

Light travels at the same speed at all times. True False

Physics

2 answers:

topjm [15]3 years ago

6 0

Answer:

true hope this help :}

Explanation:

Airida [17]3 years ago

3 0

The answer is true for this

You might be interested in

Two vectors, A and B, have magnitudes of 10 and 15. The cross product of these vectors has magnitude 32. What is the angle betwe

zalisa [80]

Answer:

The Angle between the vector A and B is 12.32°

Explanation:

Given data

|A×B|=32

|A|=10

|B|=15

To find

Angle α

Solution

From Cross product properties we know that

$|A*B|=|A||B|Sin\alpha \\32=(10)(15)Sin\alpha\\Sin\alpha=32/150\\\alpha =Sin^{-1}(32/150)\\\alpha =12.32^{o}$

The Angle between the vector A and B is 12.32°

7 0

3 years ago

Read 2 more answers

if pete (mass =90.00kg) weighs himself and finds that he weighs 30.0 pounds, how far away from the earth is he?

Svet_ta [14]

Here we know that mass of the person is 90 kg

His weight is given as 30 lbf

so here we can convert it into Newton as we know that

1 lbf = 4.45 N

Now from above conversion

$30 lbf = 30 \times 4.45 = 133.45 N$

now we can use this to find the gravity at this height

$mg = 133.45$

$90\times g = 133.45$

$g = 1.49 m/s^2$

now we know that with height gravity varies as

$g' = g(\frac{R}{R+H})^2$

$1.49 = 9.8(\frac{6.37\times 10^6}{6.37\times 10^6 + h})^2$

$h = 1.0 \times 10^7 m$

so above is the height from the surface of earth

4 0

3 years ago

If the ball goes out over the endline and a

Tju [1.3M]

Explanation:

$arw.......i \: think : it \: should \: be \: corner \: kick$

7 0

3 years ago

Think of three questions that will help you clarify your understanding of how of the factors that have contributed to the rise i

fenix001 [56]

Answer:

the glucose in air will solidify and it will stop the process.

it will cause hot air

6 0

3 years ago

Read 2 more answers

If an object has a kinetic energy of 30 j and mass of 34kg how fast is the object moving ?

BartSMP [9]

Since the formula for kinetic energy is:

Ek = (m*V^2) / 2 where m is mass and V is speed, then we can take this equation and manipulate it a little to isolate the speed.

Ek = mv^2 / 2 — multiply both sides by 2
2Ek = mv^2 — divide both sides by m
2Ek / m = V^2 — switch sides
V^2 = 2Ek / m — plug in values
V^2 = 2*30J / 34kg
V^2 = 60J/34kg
V^2 = 1.76 m/s — sqrt of both sides
V = sqrt(1.76)
V = 1.32m/s (roughly)

4 0

3 years ago