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Yanka [14]
2 years ago
7

Calculate cos0 to two decimal places.

Mathematics
1 answer:
stealth61 [152]2 years ago
8 0
I see the picture but its really bad so 5.-2
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Solve for x leave answer as decimal <br> 6/5=x/3
777dan777 [17]

Answer:

3 3/5 =x

3 .6 =x

Step-by-step explanation:

6/5 = x/3

Use cross products

6*3 = 5*x

18 = 5x

Divide each side by 5

18/5 = 5x/5

18/5 =x

3 3/5 =x

8 0
3 years ago
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What is the area of the rhombus below?
Maurinko [17]

Answer:

C

130 Units 2

Step-by-step explanation:

Hope this helps:)

7 0
2 years ago
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2. Trapezoid WXYZ is located at W(2.1) X[3.
Nataliya [291]

Point Y is (6, -1)

Subtract 6 from the y coordinate in point y since it is translated down. keep the x coordinate since it is only being translated up and down, or by the y axis

5 0
3 years ago
Graph y-3 = 1/2 (x+2)
jenyasd209 [6]

Answer:

Step-by-step explanation:

first solve for y=mx+ b format

y-3= 1/2(x+2)

y-3= 1/2x+1

y= 1/2x+4

slope is 1/2; y-intercept is 4

Download pdf
8 0
3 years ago
Use​ Newton's method to find an approximate solution of ln(x)=10-x. Start with x_0 =9 and find x_2 .
vova2212 [387]

Answer:

x₂ = 7.9156

Step-by-step explanation:

Given the function  ln(x)=10-x with initial value x₀ = 9, we are to find the second approximation value x₂ using the Newton's method. According to Newtons method xₙ₊₁ = xₙ -  f(xₙ)/f'(xₙ)

If f(x) = ln(x)+x-10

f'(x) = 1/x + 1

f(9) = ln9+9-10

f(9) = ln9- 1

f(9) = 2.1972 - 1

f(9) = 1.1972

f'(9) = 1/9 + 1

f'(9) = 10/9

f'(9) = 1.1111

x₁ = x₀ -  f(x₀)/f'(x₀)

x₁ = 9 -  1.1972/1.1111

x₁  = 9 - 1.0775

x₁  = 7.9225

x₂ = x₁ -  f(x₁)/f'(x₁)

x₂ = 7.9225 -  f(7.9225)/f'(7.9225)

f(7.9225) = ln7.9225 + 7.9225 -10

f(7.9225) = 2.0697 + 7.9225 -10

f(7.9225) = 0.0078

f'(7.9225) = 1/7.9225 + 1

f'(7.9225) = 0.1262+1

f'(7.9225) = 1.1262

x₂ = 7.9225 - 0.0078/1.1262

x₂ = 7.9225 - 0.006926

x₂ = 7.9156

<em>Hence the approximate value of x₂ is 7.9156</em>

7 0
3 years ago
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