For (a): Since AC is parallel to A'C' and A'D is a transversal for these two parallel lines, so, ∠CDB' = ∠B'A'C', because these are alternate interior angles.

For (b): Since BC is parallel to B'C' and A'B' is a transversal, so ∠BEB' = ∠A'B'C', because these are alternate interior angles.

For (c): Since AB is parallel to A'B' and AD is a transversal, so ∠BAC = ∠CDB', because these are alternate interior angles.

For (d): Since AB is parallel to A'B' and BE is a transversal, so ∠ABC = ∠BEB', because these are alternate interior angles.

Thus, all the questions marks are the reasons that the given angles are equal because they are alternate interior angles.

5 0

3 years ago

Solve for u in terms of s, t, and v. t = u + s + v

harina [27]

Answer:

$t = u + s + v \\ \boxed{u = t - s - v}$

u = t-s-v is the right answer.

7 0

2 years ago

PLEASE HELP ME 1.4t − 0.4 (t−3.1) = 5.8 t=?

dimulka [17.4K]

1.4t - 0.4 (t-3.1) = 5.8

I came out with t = 4.56

5 0

3 years ago