<span>A Learner’s license is available to those at least 15 years old that have passed the written and vision tests.
</span><span>An intermediate license, you must be 16 or 17 years old and you must have held a learner’s license for at least 12 months without receiving any traffic violations.</span>
        
             
        
        
        
Answer:
Water breaking down into hydrogen and oxygen is a decomposition reaction
Hydrogen and oxygen combining to form water is a synthesis reaction
Explanation:
A decomposition reaction is a chemical reaction that involves the breakdown of a chemical reactant entity into two or more simpler product fragments
Water H₂O undergoes a decomposition reaction by breaking down into hydrogen, H₂,, and oxygen, O₂, as follows;
2H₂O (l) → 2H₂ (g) + O₂ (g)
A synthesis reaction is a reaction that involves the chemical combination of two or more dissimilar molecules or atoms to produce a different compound or molecule
Water, H₂O, is formed by a synthesis reaction of hydrogen, H₂,, and oxygen, O₂, combining as follows;
2H₂ + O₂  → 2H₂O
 
        
             
        
        
        
Answer:
Choice A: approximately 
, assuming that the two pistons are connected via some confined liquid to form a simple machine. 
Explanation:
Assume that the two pistons are connected via some liquid that is confined. Pressure from the first piston:
.
By Pascal's Principle, because the first piston exerted a pressure of 
 on the liquid, the liquid will now exert the same amount of pressure on the walls of the container. 
Assume that the second piston is part of that wall. The pressure on the second piston will also be 
. In other words:
.
To achieve a force of 
, the surface area of the second piston should be:
.
 
        
             
        
        
        
Answer:
Explanation:
24 - gauge wire , diameter = .51 mm . 
Resistivity of copper ρ = 1.72 x 10⁻⁸ ohm-m
R = ρ l / s 
1.72x 10⁻⁸ / [3.14 x( .51/2)² x 10⁻⁶ ]
= 8.42 x 10⁻² ohm 
= .084 ohm 
B )  Current required through this wire
= 12 / .084 A
= 142.85 A
C ) 
Let required length be l 
resistance = .084 l 
2 = 12 / .084 l 
l = 12 / (2 x .084)
= 71.42 m 
 
        
                    
             
        
        
        
Time t=2.4 minutes=2.4×60=144 seconds
distance s=1.2 miles=1.2×1609=1930.8 meters
speed v=s/t=1930.8÷144=[tex] \frac{1930.8}{144} = \frac{160.9}{12} =[/13.408m/s ~nearly]