All categories

3 years ago

Calculate the density of oxygen,

Chemistry

1 answer:

abruzzese [7]3 years ago

5 0

Answer:

density of oxygen = 1.307 g/l

Explanation:

given pressure = 1 atm temperature = 298 k

PM=DRT

where p is pressure M is molecular mass D is density R is gas constant and T is temperature

substituting the values in the equation

$1\times 32=D\times 0.0821\times 298$

D = 1.307 g/l.

You might be interested in

Looking at the periodic table, which of these elements has the smallest atomic radius?

Triss [41]

Flourine I guess must be the answer

5 0

3 years ago

Steam reforming of methane ( CH4 ) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas, which is the sta

Hatshy [7]

Answer: The pressure equilibrium constant for the reaction is 1473.8

Explanation:

We are given:

Initial partial pressure of methane gas = 2.4 atm

Initial partial pressure of water vapor = 3.9 atm

Equilibrium partial pressure of hydrogen gas = 6.5 atm

The chemical equation for the reaction of methane gas and water vapor follows:

$CH_4+H_2O\rightleftharpoons CO+3H_2$

Initial: 2.4 3.9

At eqllm: 2.4-x 3.9-x x 3x

Evaluating the value of 'x':

$\Rightarrow 3x=6.5\\\\x=2.167$

So, equilibrium partial pressure of methane gas = (2.4 - x) = [2.4 - 2.167] = 0.233 atm

Equilibrium partial pressure of water vapor = (3.9 - x) = [3.9 - 2.167] = 1.733 atm

Equilibrium partial pressure of carbon monoxide gas = x = 2.167 atm

The expression of $K_p$ for above equation follows:

$K_p=\frac{p_{CO}\times (p_{H_2})^3}{p_{CH_4}\times p_{H_2O}}$

Putting values in above equation, we get:

$K_p=\frac{2.167\times (6.5)^3}{0.233\times 1.733}\\\\K_p=1473.8$

Hence, the pressure equilibrium constant for the reaction is 1473.8

5 0

4 years ago

Is. Mg(s) --------------> Mg2+(aq) + 2e− oxidation or reduction?

Kruka [31]

Answer:

Oxidation

Explanation:

Mg loses 2e- for it to gain it's stability hence the reaction above is oxidation

note: Oxidation is the loss of electrons while reduction is the gain of electrons

5 0

3 years ago

5. The Rf of ibuprofen was found to be 0.32 when t-butyl methyl ether was used as the development solvent. What effect would the

Lady_Fox [76]

Answer:

The Rf value of ibuprofen increases

Explanation:

TLC involves the elution of a solute using a mobile phase(solvent). The stationary phase is made of an adsorbent such as silica.

The extent of interaction between the solute and the mobile phase affects the Rf value. The greater the interaction between the solute and the solvent, the greater the Rf value.

On the other hand, the polarity of the solvent and the solute also affects the Rf value. If the solvent is changed from t-butyl methyl ether to acetone, the Rf value for ibuprofen increases because ibuprofen is polar and acetone is also polar hence there is greater interaction between the solvent and solute.

3 0

3 years ago

How many moles of NH3 are produced in the reaction of 3.3 moles of N2? N2 + 3H2 = 2NH3

enot [183]

Answer:

6.6 moles of NH3

Explanation:

3.3 mol N2 * (2 mol NH3/ 1 mol N2) = 6.6 mol NH3

6 0

2 years ago