The specific gravity is how the density of the object compares to the density of water. Water's density is 1gram per milliliter. We just need to figure out the density of the object.
The object is .8 kg and it displaces 500mL of water, so the density is the mass divided by the volume. Since the density of water is given in grams, we have to convert the objects mass from kg to g and then we can get the density.
.8kg * 1000g/kg = 800 grams
So
800g/500ml = 1.6grams/mL this is the density.
So divide the density of your object by the density of water, which is 1g/mL, you get 1.6 as the specific gravity. This means the object is 1.6 times more dense than water.
Answer:
A. 54.88m/s.
B. 153.66m
Explanation:
Data obtained from the question include:
Time (t) = 5.6 secs
A. Determination of the skydiver's downward velocity.
Time (t) = 5.6 secs
Acceleration due to gravity (g) = 9.8m/s²
Velocity (v) =..?
v = gt
v = 9.8 x 5.6
v = 54.88m/s
Therefore, the skydiver's downward velocity is 54.88m/s
B. Determination of the height below the helicopter.
Time (t) = 5.6 secs
Acceleration due to gravity (g) = 9.8m/s²
Height (H) =..?
H = ½gt²
H = ½ x 9.8 x 5.6²
H = 153.66m
Therefore, the height below the helicopter when the parachute opens is 153.66m.
The shoreline is the line where the very tippy tip
of the water stops and the dry sand or dirt starts.
It's the boundary line between water and land.
8a2-10ab+15b+10 Explaintion: