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Natasha2012 [34]
3 years ago
10

What is the formula you use to determine the gravitational potential energy of a object

Physics
1 answer:
kozerog [31]3 years ago
4 0

Gravitational potential energy, relative to some level =

       (mass of the object)
times
       (height above the reference level)
times
       (acceleration due to gravity) .
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Standing still, Bruce, the quarterback, gets tackled by Biff, the 90.0-kg tackle, who is traveling at 7.0 m/s. Upon collision, B
tatyana61 [14]

\\ \sf\longmapsto \Delta P=P

\\ \sf\longmapsto m1v1=m2v2

\\ \sf\longmapsto 90(7)=m2(10)

\\ \sf\longmapsto 10m2=630

\\ \sf\longmapsto m2=\dfrac{630}{10}

\\ \sf\longmapsto m2=63kg

Bruces mass is 63kg

3 0
2 years ago
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A bullet of mass m=26g is fired into a wooden block of mass M=4.7kg. The block is attached to a string of length 1.5m. The bulle
vodka [1.7K]

Answer:

u = 449 m/s

Explanation:

Given,

Mass of the bullet, m = 26 g

Mass of the wooden block,M = 4.7 Kg

height of the block,h = 0.31 m

initial speed of the block, u = ?

Using conservation of energy

(M+ m)gh = \dfrac{1}{2}(M+m)v^2

gh = \dfrac{1}{2}v^2

v=\sqrt{2gh}

v=\sqrt{2\times 9.81\times 0.31}

v = 2.47 m/s

Now, using conservation of momentum to calculate the speed of the bullet.

m u + M u' = (M+m)v

m u  = (M+m)v

0.026 x u  = (4.7+0.026) x 2.47

u = 449 m/s

Hence, the speed of the bullet is equal to 449 m/s.

5 0
2 years ago
What is the speed of an object after falling (from rest) a distance of 9.80 meters near the surface of the Earth? Assume air
madam [21]

Hi there!

We can use the kinematic equation:

v_f^2 = v_i^2 + 2ad

vf = Final velocity (? m/s)

vi = initial velocity (0 m/s, dropped from rest)

a = acceleration (due to gravity, 9.8 m/s²)

d = distance (9.8 m)

Simplify the equation to solve for vf:

v_f^2 = 0 + 2ad\\\\v_f = \sqrt{2ad}

Substitute in the given values:

v_f = \sqrt{2(9.8)(9.8)} = \boxed{13.86 m/s}

8 0
2 years ago
In space (no gravity or friction), you throw a ball with mass 0.1 kg at a target with mass 1 kg. You throw the ball at a speed o
ioda

Answer:

Explanation:

We shall apply law of conservation of  momentum in space to know the velocity of combination after the impact

m₁v₁ = m₂v₂

.1 x 4 = ( 1 + .1 ) v₂

v₂ = .3636 m /s

1  )  

Kinetic energy of the combination

= 1/2 x 1.1 x ( .3636)²

= 7.3 x 10⁻² J

2 )

Initial kinetic energy of the system

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Final  kinetic energy of the system = 7.3 x 10⁻²

Loss of energy = .8 - .073

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This energy was converted into internal energy of the system .

3 )

increase in entropy = dQ / T

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6 0
3 years ago
What is a prediction
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A prediction is a guess of something happening in the future.

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3 years ago
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