The name of the molecule above is <u>Ethene</u>
<h3>What are organic compounds?</h3>
Organic compounds can be defined as compounds containing carbon and hydrogen.
Some classes of organic compounds are:
- Alkanes
- Alkenes
- Alkanols
- Alkanals
- Alkynes
So therefore, he name of the molecule above is Ethene
Learn more about organic compounds:
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Answer:
a.Low temperature
Explanation
Equation of reaction:
2NO2 <==> N2O4(g) ∆H = +ve
To cause the reaction to become darker brown means to produce more of NO2 gas. That is backward reaction.
Since the reaction is endothermic, decrease in temperature will shift the equilibrium position to the left thereby favouring backward reaction. This is in line with Me Chatelier's principle.
High pressure will rather favour forward reaction (it is not the right option).
The kinetic energy of a moving object is calculated through the equation,
KE = 0.5mv²
where KE is kinetic energy, m is mass, and v is the velocity. Substituting the known values in the problem above,
KE = 0.5(55 kg)(16 m/s)²
KE = 7,040 J
Thus, the kinetic energy of the skydiver is approximately equal to 7 kJ.
The answer to this question would be liquid.
<span>Lipids with high polyunsaturated fatty acid mostly found as a liquid, but the saturated one would be solid at room temperature. A molecule with higher molecular weight will have the higher boiling point and it more likely to be solid at room temperature.
Unsaturated fat is more healthy than saturated fat and it is recommended to reduce saturated fat consumption as it was linked to many diseases.
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1 answer · Chemistry
Best Answer
Water steam condenses if its pressure is equal to vapor saturation vapor pressure.
Use the Clausius-Clapeyron relation.
I states the temperature gradient of the saturation pressure is equal to the quotient of molar enthalpy of phase change divided by molar volume change due to phase transition time temperature:
dp/dT = ΔH / (T·ΔV)
Because liquid volume is small compared to vapor volume
ΔV in vaporization is approximately equal to to the vapor volume. Further assume ideal gas phase:
ΔV ≈ V_v = R·T/p
Hence
dp/dT = ΔHv / (R·T²/p)
<=>
dlnp/dT = ΔHv / (R·T²)
If you solve this DE an apply boundary condition p(T₀)= p₀.
you get the common form:
ln(p/p₀) = (ΔHv/R)·(1/T₀ - 1/T)
<=>
p = p₀·exp{(ΔHv/R)·(1/T₀ - 1/T)}
For this problem use normal boiling point of water as reference point:
T₀ =100°C = 373.15K and p₀ = 1atm
Therefore the saturation vapor pressure at
T = 350°C = 623.15K
is
p = 1atm ·exp{(40700J / 8.314472kJ/mol)·(1/373.15K - 1/623.15K)} = 193 atm
hope this helps
