Ask question

Ask question

All categories

2 years ago

5

One least interesting thing about collisions?

1 answer:

luda_lava [24]2 years ago

5 0

A change in momentum is called impulse.

You might be interested in

If an object is to rest on an incline without slipping, then friction must equal the component of the weight of the object paral

leonid [27]

Answer:

$\theta = tan^{-1}\mu$

Explanation:

As we know that if the object is placed on the inclined plane then the force of friction on the object is counterbalanced by the component of the weight of the object along the inclined plane.

So we can say

$F_f = mgsin\theta$

now if we increase the inclination of the plane then the component of the weight weight along the inclined plane will increase and hence the friction force will also increase.

As we know that the limiting value or the maximum value of friction force at the static condition is given by

$F_f = \mu N$

$N = mg cos\theta$

so we have

$F_f = \mu (mg cos\theta)$

so we will have

$mg sin\theta = \mu (mg cos\theta)$

so now we have

$tan\theta = \mu$

so maximum possible angle of the inclined plane is

$\theta = tan^{-1}\mu$

3 0

3 years ago

How many Oxygen (O) atoms are in the following? H2O + CO2<br><br> 4<br><br> 3<br><br> 2

Contact [7]

There are 3 oxygen atoms

6 0

3 years ago

At a stoplight, a truck traveling at 15 m/s passes a car as it starts from rest. The truck travels at constant velocity and the

Art [367]

The time that the car take to catch up to truck would be :

1/2 ar^2 = vt

1/2 (3) t^2 = 15t

1.5 t^2 = 15t

t ^2 = 10s

Hope this helps

4 0

3 years ago

A pendulum on plant X is 0.25 meters long and the period is 4 seconds. What is “g” on Planet X?

Monica [59]

Answer:

The value of g = 0.6168 m/s².

Explanation:

Given that,

On a planet X,

Length of the pendulum(L) = 0.25 meters,

Time period of the pendulum(T) = 4 seconds.

We have to find the 'g' value on the planet.

The 'g' value on a planet can be found by a pendulum with help of the formula,

T = 2π × $\frac{\sqrt{L} }{\sqrt{g} }$

From this, g = 4π² × $\frac{L}{T^{2} }$

Using the above formula and substituting the values,we get,

g = 0.6168 m/s².

7 0

3 years ago

Which biome's yearly rainfall mainly evaporates?

tino4ka555 [31]

India's monsoon area i beleive

7 0

3 years ago

Read 2 more answers