<u>Answer:</u> The number of moles of carbon dioxide produced are and the mass of calcium carbonate is 61.6 mg
<u>Explanation:</u>
To calculate the moles of carbon dioxide gas, we use the equation given by ideal gas which follows:
where,
P = pressure of the gas = 738.0 mmHg
V = Volume of the gas = 15.5 mL = 0.0155 L (Conversion factor: 1 L = 1000 mL)
T = Temperature of the gas =
R = Gas constant =
n = number of moles of carbon dioxide gas = ?
Putting values in above equation, we get:
For the given chemical equation:
By Stoichiometry of the reaction:
1 mole of carbon dioxide gas is produced from 1 mole of calcium carbonate
So, of carbon dioxide will be produced from = of calcium carbonate
- To calculate the mass for given number of moles, we use the equation:
Molar mass of calcium carbonate = 100 g/mol
Moles of calcium carbonate =
Putting values in above equation:
Converting this into milligrams, we use the conversion factor:
1 g = 1000 mg
So,
Hence, the number of moles of carbon dioxide produced are and the mass of calcium carbonate is 61.6 mg