The answer for the following question is explained below.
- <u><em>Therefore the work done is 130 kilo Joules.</em></u>
Explanation:
Work:
A force causing the movement or displacement of an object.
Given:
mass of the person (m) = 65 kg
height of the cliff (h) = 2000 m
To calculate:
work done (W)
We know;
According to the formula:
<u>W = m × g × h</u>
Where;
m represents mass of the person
g represents the acceleration due to gravity
where the value of g is;
<u> g = 10 m/ s²</u>
h represents the height of the cliff
From the above formula;
W = 65 × 10 × 2000
W = 130,000 J
W = 130 Kilo Joules
<u><em>Therefore the work done is 130 kilo Joules.</em></u>
Answer:
Traditional methods of measurement involve methods like measurement using the arm, foot or hand span of a particular person which can and does varies form person to person and hence can't be reliable while the standard methods have a fixed standard value which is universal and same for everybody and every place and ..
Answer
3.340J
Explanation;
Using the relation. Energy stored in capacitor = U = 7.72 J
U =(1/2)CV^2
C =(eo)A/d
C*d=(eo)A=constant
C2d2=C1d1
C2=C1d1/d2
The separation between the plates is 3.30mm . The separation is decreased to 1.45 mm.
Initial separation between the plates =d1= 3.30mm .
Final separation = d2 = 1.45 mm
(A) if the capacitor was disconnected from the potential source before the separation of the plates was changed, charge 'q' remains same
Energy=U =(1/2)q^2/C
U2C2 = U1C1
U2 =U1C1 /C2
U2 =U1d2/d1
Final energy = Uf = initial energy *d2/d1
Final energy = Uf =7.72*1.45/3.30
(A) Final energy = Uf = 3.340J
Answer:
A) 10 m/s
Explanation:
We know that according to conservation of momentum,
m1v1 + m2v2 = m1u1 + m2u2 ..............(equation 1)
where m1 and m2 are masses of two bodies, v1 and v2 are initial velocity before collision and u1 and u2 are final velocities after collision respectively.
From the given data
If truck and car are two bodies
truck : m1 = 2000 Kg v1 = 5 m/s u1 = 0
car : m2 = 1000 kg v2 = 0 u2 = ?
final velocity of truck and initial velocity of car are static because the objects were at rest in the respective time.
substituting the values in equation 1, we get
(2000 x 5) + 0 = 0 + (1000 x u2)
u2 = 
x 5
= 10 m/s
Hence after collision, car moves at a velocity of 10 m/s
Answer:
0.91 J
Explanation:
The kinetic energy of an object is given by
where
m is the mass of the object
v is its speed
For the lemming in this problem, when he jumps, we have:
m = 0.0780 kg is the mass
v = 4.84 m/s is the speed
Substituting into the equation, we find:
