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allochka39001 [22]
3 years ago
15

Which of the following molecules would you expect to have a dipole moment of zero? a,CH2 Ch3

Chemistry
1 answer:
Vadim26 [7]3 years ago
4 0

Answer: The molecule CH_{3}-CH_{3} is expected to have a dipole moment of zero.

Explanation:

The product of magnitude of the charge calculated in electrostatic units is called dipole moment.

Formula for dipole moment is as follows.

Dipole moment = Charge (in esu) \times distance (in cm)

Non-polar molecules have zero dipole moment.

For example, CH_{3}-CH_{3} is a non-polar molecule so its dipole moment is zero.

H_{2}C=O is a polar molecule so it will have dipole moment.

CH_{2}Cl_{2} is a polar molecule so it will have dipole moment.

NH_{3} has nitrogen atom as more electronegative than hydrogen atom. So, net dipole moment will be in the direction of nitrogen atom.

Thus, we can conclude that the molecule CH_{3}-CH_{3} is expected to have a dipole moment of zero.

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Mg(OH)2 + 2HNO3 → Mg(NO3)2 + 2H20
LenaWriter [7]

Answer:

A. 1350

You multiply 18.21HNO3* 1mol MgN2O6 * 148.30MgN2O6

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3 0
3 years ago
4.a) Draw two Lewis structures for HCP; one where C is central and one where P is central: b) Calculate formal charge for each a
love history [14]

One Hydrogen atom (H) and one Oxygen atom (O) surround the central Carbon atom (C) in the HCP Lewis structure (O). Carbon (C) and Phosphorus (P) have a triple bond, and Carbon (C) and Hydrogen (H) have a single bond.

<h3>How can you choose the ideal format for a formal charge?</h3>

The Lewis structure with the negative formal charges on the most electronegative atoms is the one to choose from when faced with a choice between numerous Lewis structures with similar formal charge distributions.

<h3>How do you determine the preferred resonance structure?</h3>

The resonance forms with the fewest non-zero formal charge atoms are selected. Resonance develops atoms that have a negative formal charge or are the most electronegative are preferred.

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brainly.com/question/20300458

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8 0
1 year ago
What is the value of work done on an object when a 50–newton force moves it 15 meters in the same direction as the force?
victus00 [196]

Answer:

work done = 750 J

Explanation:

Given data:

Force on object = 50 N

Distance covered = 15 m

Work done = ?

Solution:

W = F. d

W = work done

F = force

d = distance

Now we will put the values in formula.

W = 50 N × 15 m

W = 750 N. m = 750 J

7 0
3 years ago
_______ are plants that produce seeds and flowers.
kiruha [24]

Answer:

angiosperms

Explanation:

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2 years ago
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