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Rainbow [258]
3 years ago
13

Covalent bonds usually occur between atoms that have and . A. High molecular weights; large atomic radii B. Low ionization energ

ies; low electron affinities C. Low molecular weights; small atomic radii D. High ionization energies; high electron affinities
Chemistry
1 answer:
Katen [24]3 years ago
8 0

Answer is: D. High ionization energies; high electron affinities.

Covalent bond is usually between nonmetals.

The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose  electrons, oxidation number of element grows (oxidation process).

Nonmetals are far right in the main group and they have highest ionization energy, because they have many valence electrons.

For example, fluorine has the greatest affinity for electrons and tendency to be reduced, than oxygen and chlorine.

Fluorine form molecule of fluorine F₂ with single nonpolar covalent bond.

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Find the hydroxide ion concentration of a HBr solution with a pH of 4.75
Sunny_sXe [5.5K]
1st find the pOH = 14 - 4.75 = 9.25
then do 10^-9.25 = 5.62x10^-10 OH- concentration
8 0
3 years ago
PLEASE HELP!!!!!!!
dsp73

Answer: 1. 2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu

2. 3 moles of CuCl_2 : 2 moles of Al

3. 0.33 moles of CuCl_2 : 0.92 moles of Al

4. CuCl_2 is the limiting reagent and Al is the excess reagent.

5. Theoretical yield of AlCl_3 is 29.3 g

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Al=\frac{25.0g}{27g/mol}=0.92moles

\text{Moles of} CuCl_2=\frac{45.0g}{134g/mol}=0.33moles

The balanced chemical equation is:

2Al+3CuCl_2\rightarrow 2AlCl_3+3Cu  

According to stoichiometry :

3 moles of CuCl_2 require = 2 moles of Al

Thus 0.33 moles of CuCl_2 will require=\frac{2}{3}\times 0.33=0.22moles  of Al

Thus CuCl_2 is the limiting reagent as it limits the formation of product and Al is the excess reagent.

As 3 moles of CuCl_2 give = 2 moles of AlCl_3

Thus 0.33 moles of CuCl_2 give =\frac{2}{3}\times 0.33=0.22moles  of AlCl_3

Theoretical yield of AlCl_3=moles\times {\text {Molar mass}}=0.22moles\times 133.34g/mol=29.3

Thus 29.3 g of aluminium chloride is formed.

5 0
2 years ago
Given the following equation, how many grams of PbCO3 will dissolve when exactly 1.0 L of 1.00 M H+ is added to 6.00 g of PbCO3?
9966 [12]
Calculating for the moles of H+
1.0 L x (1.00 mole / 1 L ) = 1 mole H+

From the given balanced equation, we can use the stoichiometric ratio to solve for the moles of PbCO3:
1 mole H+ x (1 mole PbCO3 / 2 moles H+) = 0.5 moles PbCO3

Converting the moles of PbCO3 to grams using the molecular weight of PbCO3
0.5 moles PbCO3 x (267 g PbCO3 / 1 mole PbCO3) = 84.5 g PbCO3
4 0
3 years ago
Read 2 more answers
did this and got 8.3 x 10-5 can someone help me figure out how i got this wrong since these are the only answer choices?
Bezzdna [24]
It is b i think bc it looks like it would be it and my tudor helped me
4 0
2 years ago
I need help on #'s 4 and 5
kompoz [17]
The answer for four is frequency.
3 0
3 years ago
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