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hodyreva [135]
3 years ago
13

A geologist finds a mineral sample alongside a swift flowing river. She determines the mineral is a type of Quartz. Which is tru

e about this mineral?
A. It cannot be classified without knowing it's end use
B. It can be classified as a silicate mineral
C.It can be classified as a carbonate
D. IT can be classified as a metallic ore
NEED THE ANSWER PLEASE HELPPP!!
Chemistry
2 answers:
Minchanka [31]3 years ago
8 0
I would say d or b sorry im not that good
svp [43]3 years ago
8 0
B-  quarts is a silicate mineral
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kramer
<span>They lower the activation energy.</span>
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A chemist prepares a sample of helium gas at a certain pressure, temperature and volume and then removes all but a fourth of the
cupoosta [38]

Answer:

The temperature must be changed to 4 times of the initial temperature so as to keep the pressure and the volume the same.

Explanation:

Pressure in the container is P and volume is V.

Temperature of the helium gas molecules =T_1

Molecules helium gas = x

Moles of helium has = n_1= \frac{x}{N_A}

PV = nRT (Ideal gas equation)

PV=n_1RT_1...[1]  

After removal of helium gas only a fourth of the gas molecules remains and pressure in the container and volume should remain same.

Molecules of helium left after removal = \frac{x}{4}

Moles of helium has left after removal = n_2= \frac{x}{4\times N_A}

PV=n_2RT_2...[2]

n_1RT_1=n_2RT_2

\frac{x}{N_A}\times T_1=\frac{x}{4\times N_A}\times T_2

T_1=\frac{T_2}{4}

T_2=4T_1

The temperature must be changed to 4 times of the initial temperature so as to keep the pressure and the volume the same.

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3 years ago
You are performing an experiment that uses 114Ag. 113Ag is radioactive, decays by beta-- emission and has a half-life of 21 minu
maxonik [38]

Answer: The 234.74 grams of sample should be ordered.

Explanation:

Let the gram of  114 Ag to ordered be N_o

The amount required for the beginning of experiment = 0.0575 g

Time requires to ship the sample = 4.2hour = 252 min(1 hr = 60 min)

Half life of the sample ={t_{\frac{1}{2}} = 21 min

\lambda =\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{21 min}=0.033 min^{-1}

\log[N]=\log[N_o]-\frac{\lambda t}{2.303}

\log[0.0575 g]=\log[N_o]-\frac{0.033 min^{-1}\times 252 min}{2.303}

N_o=234.74 grams

The 234.74 grams of sample should be ordered.

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3 years ago
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sergejj [24]

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Each chemical compound is always represented by a chemical symbol, which shows the ratio at which each atom of the elements of the compound are combine together and this is often used in naming the compound. Looking at the compound given in the question, the compound is made up of two atoms of nitrogen and three atoms of oxygen and this fact was used in naming the compound. In naming chemical compounds, 'Di' stands for 2 while 'Tri' stands for 3. Since there are two nitrogen and three oxygen atoms in the compound, that was why it was named dinitrogen trioxide.

3 0
2 years ago
Read 2 more answers
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