Question

10. a. What is the binding energy released when an alpha particle of mass 6.64 x 10-27 kg escapes from the nucleus of Uranium- 238? C = 3.00 x 108m/s. Give formula. show substitutions, and answer

Answer 1

Answer:

The binding energy released is 1.992 X 10⁻¹⁸ J

Explanation:

Given;

mass of the alpha particle, m = 6.64 x 10⁻²⁷ kg

speed of the alpha particle, c = 3 x 10⁸ m/s

The binding energy released is given by;

$E_b = mc^2$

where;

m is mass of the particle

c is speed of the particle

E = 6.64 x 10⁻²⁷ (3 x 10⁸)²

E = 1.992 X 10⁻¹⁸ J

Therefore, the binding energy released is 1.992 X 10⁻¹⁸ J