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il63 [147K]
3 years ago
9

Determine the molality and molarity of a sodium chloride solution prepared by adding 52.80 g of solid NaCl to 150.0 g of water.

The density of the saline solution is 1.1972 g mL . Molality
Chemistry
1 answer:
ss7ja [257]3 years ago
6 0

Answer:

  • 6.02 m
  • 5.334 M

Explanation:

First we <u>convert 52.80 g of NaCl to moles</u>, using its <em>molar mass</em>:

  • 52.80 g ÷ 58.44 g/mol = 0.9035 mol

To determine the molality, we <u>convert 150.0 g of water to kg</u>:

  • 150.0 g / 1000 = 0.150 kg
  • molality = 0.9035 mol / 0.150 kg =  6.02 m

As for the molarity, we <u>determine the total mass of solution</u>:

  • 52.80 g + 150.0 g = 202.8 g

And <u>calculate the volume</u>, using the <em>density</em>:

  • 202.8 g ÷ 1.1972 g/mL = 169.39 mL
  • 169.39 mL / 1000 = 0.16939 L

Finally we <u>calculate the molarity</u>:

  • 0.9035 mol / 0.16939 L = 5.334 M
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oee [108]

This is an incomplete question, here is a complete question.

The equilibrium constant is equal to 5.00 at 1300 K for the reaction:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

If initial concentrations are [SO₂] = 1.20 M, [O₂] = 0.45 M, and [SO₃] = 1.80 M, the system is

A) at equilibrium.

B) not at equilibrium and will remain in an unequilibrated state.

C) not at equilibrium and will shift to the left to achieve an equilibrium state.

D) not at equilibrium and will shift to the right to achieve an equilibrium state.

Answer : The correct option is, (A) at equilibrium.

Explanation :

Reaction quotient (Q) : It is defined as the measurement of the relative amounts of products and reactants present during a reaction at a particular time.

The given balanced chemical reaction is,

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

The expression for reaction quotient will be :

Q=\frac{[SO_3]^2}{[SO_2]^2[O_2]}

In this expression, only gaseous or aqueous states are includes and pure liquid or solid states are omitted.

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Q=\frac{(1.80)^2}{(1.20)^2\times (0.45)}=5.0

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There are 3 conditions:

When Q>K_c that means product > reactant. So, the reaction is reactant favored.

When Q that means reactant > product. So, the reaction is product favored.

When Q=K_c that means product = reactant. So, the reaction is in equilibrium.

From the above we conclude that, the Q=K_c that means product = reactant. So, the reaction is in equilibrium.

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