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3 years ago

the table below shows the effect conditions on a car stopping distance. in witch condition was the car travelling most slowly

Physics

1 answer:

nikdorinn [45]3 years ago

7 0

Answer: Car 5

Explanation:

Higher speeds mean higher braking times so the car with the highest braking distance was travelling the the fastest and the car with the lowest braking distance was traveling the slowest.

Braking distance = Stopping distance - Thinking distance.

Car Braking distance

1 38

2 50 = 65 - 15

3 75

4 75

5 14 = 23 - 9

Car 5 had the lowest braking distance so was going the slowest.

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3 years ago

A 1.2 kg ball drops vertically onto a floor from a height of 32 m, and rebounds with an initial speed of 10 m/s.

iren [92.7K]

Explanation:

Given that,

Mass of the ball, m = 1.2 kg

Initial speed of the ball, u = 10 m/s

Height of the floor from ground, h = 32 m

(a) Let v is the final speed of the ball. It can be calculated using the conservation of energy as :

$\dfrac{1}{2}mv^2=mgh$

$v=\sqrt{2gh}$

$v=\sqrt{2\times 9.8\times 32}$

v = -25.04 m/s (negative as it rebounds)

The impulse acting on the ball is equal to the change in momentum. It can be calculated as :

$J=m(v-u)$

$J=1.2\times (-25.04-10)$

J = -42.048 kg-m/s

(b) Time of contact, t = 0.02 s

Let F is the average force on the floor from by the ball. Impulse acting on an object is given by :

$J=\dfrac{F}{t}$

$F=J\times t$

$F=42.048\times 0.02$

F = 0.8409 N

Hence, this is the required solution.

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3 years ago

You should be particularly careful a restraining a struggling rabbit because it can

Shtirlitz [24]

You have no options here so I'll just answer. It can cause a rise in heart rate and greatly increases the risk of overheating and even death. If you grab the rabbit too hard, you risk breaking/fracturing a bone or causing other kinds of damage, whether externally or internally, to the rabbit.

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4 years ago

A rock is dropped from a height of 3,245 m. If we ignore air resistance, how fast will it be travelling after it falls for 3.4 s

Marta_Voda [28]

Answer:

954.4m/s

Explanation:

For a free falling object,it has constant acceleration and a changing velocity.

By using the velocity-time formula, the velocity can be obtained.

The height the rock travelled is the distance.

From,

Velocity (v) = Distance (d) / Time(t)

v = 3245m/3.4s

v = 954.4m/s

That js the answer I got. Hope it's right.

3 0

3 years ago

the table below shows the effect conditions on a car stopping distance. in witch condition was the car travelling most slowly​

the table below shows the effect conditions on a car stopping distance. in witch condition was the car travelling most slowly