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2 years ago

the table below shows the effect conditions on a car stopping distance. in witch condition was the car travelling most slowly

Physics

1 answer:

nikdorinn [45]2 years ago

7 0

Answer: Car 5

Explanation:

Higher speeds mean higher braking times so the car with the highest braking distance was travelling the the fastest and the car with the lowest braking distance was traveling the slowest.

Braking distance = Stopping distance - Thinking distance.

Car Braking distance

1 38

2 50 = 65 - 15

3 75

4 75

5 14 = 23 - 9

<em>Car 5 had the lowest braking distance so was going the slowest. </em>

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Read 2 more answers

A bicycle rider traveling east at 10 km/hr sees a blue car pass her appearing to travel west at 50 km/hr. What is the blue car's

BigorU [14]

Answer:

$v_{bR} = 25 km/h$ towards west

Explanation:

As we know that the speed of the blue car as appear to the bicycle rider is given as

$v_{bc} = 50 km/h$ towards west

also it is given that bicycle is moving at speed of 10 km/h towards East

so here we have

$v_{bc} = v_b - v_c$

so we have

$v_b = v_{bc} + v_c$

$v_b = -50 + 10 = 40 km/h$ towards west

now speed of the red car is given as 15 km/h towards west

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3 years ago

A block of mass 57.1 kg rests on a slope having an angle of elevation of 28.3°. If pushing downhill on the block with a force ju

stira [4]

Answer:

The coefficient is 0.90

Explanation:

Drawing a diagram makes thing easier, we will assume that the acceleration tends to zero because it start barely moving.

$-F_s+mg*sin(\theta)+F=0\\F_s=57.1kg*9.8m/s^2*sin(28.3)+177N\\F_s=442N\\F_s=\µ*N\\N=m*g*cos(\theta)\\N=57.1*9.8*cos(28.3)=493N\\\\\µ=\frac{442N}{493N}=0.90$

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2 years ago

the table below shows the effect conditions on a car stopping distance. in witch condition was the car travelling most slowly​

the table below shows the effect conditions on a car stopping distance. in witch condition was the car travelling most slowly